javascript .charCodeAt() 的 Java 等效项
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Java equivalent for .charCodeAt()
提问by syb0rg
In JavaScript, .charCodeAt()returns a Unicode value at a certain point in the string which you pass to a function. If I only had one character, I could use the code below to get the Unicode value in Java.
在 JavaScript 中，.charCodeAt()在传递给函数的字符串中的某个点返回一个 Unicode 值。如果我只有一个字符，我可以使用下面的代码来获取 Java 中的 Unicode 值。
public int charCodeAt(char c) {
int x;
return x = (int) c;
}
If I had a string in Java, how would I get the Unicode value of one individual character within the string, like the .charCodeAt()function does for JavaScript?
如果我在 Java 中有一个字符串，我将如何获取字符串中单个字符的 Unicode 值，就像该.charCodeAt()函数对 JavaScript 所做的那样？
回答by jlordo
Java has the same method: Character.codePointAt(CharSequence seq, int index);
Java 也有同样的方法：Character.codePointAt(CharSequence seq, int index);
String str = "Hello World";
int codePointAt0 = Character.codePointAt(str, 0);
回答by Aadit M Shah
Try this:
试试这个：
public int charCodeAt(String string, int index) {
return (int) string.charAt(index);
}
回答by Alejandro Teixeira Mu?oz
There is the way to filter the special characters you need. Just check the ASCIITable
有一种方法可以过滤您需要的特殊字符。只需检查ASCII表
Hope it helps
希望能帮助到你
public class main {
public static void main(String args[]) {
String str = args[0];
String bstr = "";
String[] codePointAt = new String[str.length()];
if (str != "")
{
for (int j = 0; j < str.length(); j++)
{
int charactercode=Character.codePointAt(str, j);
//CHECK on ASCII TABLE THE SPECIAL CHARS YOU NEED
if( (charactercode>31 && charactercode<48) ||
(charactercode>57 && charactercode<65) ||
(charactercode>90 && charactercode<97) ||
(charactercode>127)
)
{
codePointAt[ j] ="&"+String.valueOf(charactercode)+";";
}
else
{
codePointAt[ j] = String.valueOf( str.charAt(j) );
}
}
for (int j = 0; j < codePointAt.length; j++)
{
System.out.println("CODE "+j+" ->"+ codePointAt[j]);
}
}
}
}
OUTPUT
输出
call with ("TRY./&asda")
CODE 0 ->T
CODE 1 ->R
CODE 2 ->Y
CODE 3 ->&46;
CODE 4 ->&47;
CODE 5 ->&38;
CODE 6 ->a
CODE 7 ->s
CODE 8 ->d
CODE 9 ->a
回答by Android Killer
short unicode = string.charAt(index);
