如何在c/c++中定义一个常量数组？
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how to define a constant array in c/c++?
提问by Andrey Pesoshin
How to define constant 1 or 2 dimensional array in C/C++? I deal with embedded platform (Xilinx EDK), so the resources are limited.
如何在 C/C++ 中定义常量一维或二维数组？我处理嵌入式平台（Xilinx EDK），所以资源有限。
I'd like to write in third-party header file something like
我想在第三方头文件中写一些类似的东西
#define MYCONSTANT 5
but for array. Like
但对于数组。喜欢
#define MYARRAY(index) { 5, 6, 7, 8 }
What is the most common way to do this?
最常见的方法是什么？
回答by sbi
In C++, the most common way to define a constant array should certainly be to, erm, define a constant array:
在 C++ 中，定义常量数组的最常见方法当然应该是定义一个常量数组：
const int my_array[] = {5, 6, 7, 8};
Do you have any reason to assume that there would be some problem on that embedded platform?
您是否有任何理由假设该嵌入式平台会出现问题？
回答by jahhaj
In C++ source file
在 C++ 源文件中
extern "C" const int array[] = { 1, 2, 3 };
In header file to be included in both C and C++ source file
在要包含在 C 和 C++ 源文件中的头文件中
#ifdef __cplusplus
extern "C" {
#endif
extern const int array[];
#ifdef __cplusplus
}
#endif
回答by jahhaj
In C++
在 C++ 中
const int array[] = { 1, 2, 3 };
That was easy enough but maybe I'm not understanding your question correctly. The above will not work in C however, please specify what language you are really interested in. There is no such language as C/C++.
这很容易，但也许我没有正确理解你的问题。以上在 C 中不起作用，但请指定您真正感兴趣的语言。没有像 C/C++ 这样的语言。
回答by undone
It's impossible to define arrayconstant using the define directive.
array使用define指令定义常量是不可能的。
回答by Ojos
I have had a similar problem. In my case, I needed an array of constants in order to use as size of other static arrays. When I tried to use the
我遇到了类似的问题。就我而言，我需要一个常量数组，以便用作其他静态数组的大小。当我尝试使用
const int my_const_array[size] = {1, 2, 3, ... };
and then declare:
然后声明：
int my_static_array[my_const_array[0]];
I get an error from my compiler:
我的编译器出现错误：
array bound is not an integer constant
So, finally I did the following (Maybe there are more elegant ways to do that):
所以，最后我做了以下（也许有更优雅的方法来做到这一点）：
#define element(n,d) ==(n) ? d :
#define my_const_array(i) (i) element(0,1) (i) element(1,2) (i) element(2,5) 0
回答by Silikiln
#include <string>
#include <iostream>
#define defStrs new string[4] { "str1","str2","str3","str4" }
using namespace std;
...
const string * strs = defStrs;
string ezpzStr = strs[0] + "test" + strs[1];
cout << ezpzStr << endl;
Took me a while to figure this out, but apparently it works like this in C++. Works on mycomputer anyway.
我花了一段时间才弄清楚这一点，但显然它在 C++ 中是这样工作的。无论如何在我的电脑上工作。
