Python 如何使用pygame创建文本输入框？
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How to create a text input box with pygame?
提问by Deps
I want to get some text input from the user in python and display what they are typing in a text box, and when they press enter, it gets stored in a string. I've looked everywhere but i just can't find anything.(I'm using pygame)
我想在 python 中从用户那里获得一些文本输入并显示他们在文本框中输入的内容，当他们按下 Enter 键时，它被存储在一个字符串中。我到处找，但找不到任何东西。（我正在使用 pygame）
回答by skrx
You can define a rectas the area of the input box. If a pygame.MOUSEBUTTONDOWNevent occurs, use the colliderectmethod of the input_boxrect to check if it collides with the event.posand then activate it by setting a activevariable to True.
您可以定义一个矩形作为输入框的区域。如果有pygame.MOUSEBUTTONDOWN事件发生，使用rect的colliderect方法input_box来检查它是否与 发生碰撞，event.pos然后通过设置一个active变量来激活它True。
If the box is active you can type something and pygame will generate pygame.KEYDOWNevents which have a unicodeattribute that you can simply add to a string, e.g. text += event.unicode. If the user presses enter, you can do something with the textstring (in the example I just print it) and reset it to ''.
如果该框处于活动状态，您可以输入一些内容，pygame 将生成pygame.KEYDOWN具有unicode您可以简单地添加到字符串的属性的事件，例如text += event.unicode. 如果用户按 Enter，您可以对text字符串执行某些操作（在示例中我只是打印它）并将其重置为''.
import pygame as pg
def main():
screen = pg.display.set_mode((640, 480))
font = pg.font.Font(None, 32)
clock = pg.time.Clock()
input_box = pg.Rect(100, 100, 140, 32)
color_inactive = pg.Color('lightskyblue3')
color_active = pg.Color('dodgerblue2')
color = color_inactive
active = False
text = ''
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
if event.type == pg.MOUSEBUTTONDOWN:
# If the user clicked on the input_box rect.
if input_box.collidepoint(event.pos):
# Toggle the active variable.
active = not active
else:
active = False
# Change the current color of the input box.
color = color_active if active else color_inactive
if event.type == pg.KEYDOWN:
if active:
if event.key == pg.K_RETURN:
print(text)
text = ''
elif event.key == pg.K_BACKSPACE:
text = text[:-1]
else:
text += event.unicode
screen.fill((30, 30, 30))
# Render the current text.
txt_surface = font.render(text, True, color)
# Resize the box if the text is too long.
width = max(200, txt_surface.get_width()+10)
input_box.w = width
# Blit the text.
screen.blit(txt_surface, (input_box.x+5, input_box.y+5))
# Blit the input_box rect.
pg.draw.rect(screen, color, input_box, 2)
pg.display.flip()
clock.tick(30)
if __name__ == '__main__':
pg.init()
main()
pg.quit()
Here's an object-oriented variant that allows you to easily create multiple input boxes:
这是一个面向对象的变体，可让您轻松创建多个输入框：
import pygame as pg
pg.init()
screen = pg.display.set_mode((640, 480))
COLOR_INACTIVE = pg.Color('lightskyblue3')
COLOR_ACTIVE = pg.Color('dodgerblue2')
FONT = pg.font.Font(None, 32)
class InputBox:
def __init__(self, x, y, w, h, text=''):
self.rect = pg.Rect(x, y, w, h)
self.color = COLOR_INACTIVE
self.text = text
self.txt_surface = FONT.render(text, True, self.color)
self.active = False
def handle_event(self, event):
if event.type == pg.MOUSEBUTTONDOWN:
# If the user clicked on the input_box rect.
if self.rect.collidepoint(event.pos):
# Toggle the active variable.
self.active = not self.active
else:
self.active = False
# Change the current color of the input box.
self.color = COLOR_ACTIVE if self.active else COLOR_INACTIVE
if event.type == pg.KEYDOWN:
if self.active:
if event.key == pg.K_RETURN:
print(self.text)
self.text = ''
elif event.key == pg.K_BACKSPACE:
self.text = self.text[:-1]
else:
self.text += event.unicode
# Re-render the text.
self.txt_surface = FONT.render(self.text, True, self.color)
def update(self):
# Resize the box if the text is too long.
width = max(200, self.txt_surface.get_width()+10)
self.rect.w = width
def draw(self, screen):
# Blit the text.
screen.blit(self.txt_surface, (self.rect.x+5, self.rect.y+5))
# Blit the rect.
pg.draw.rect(screen, self.color, self.rect, 2)
def main():
clock = pg.time.Clock()
input_box1 = InputBox(100, 100, 140, 32)
input_box2 = InputBox(100, 300, 140, 32)
input_boxes = [input_box1, input_box2]
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
for box in input_boxes:
box.handle_event(event)
for box in input_boxes:
box.update()
screen.fill((30, 30, 30))
for box in input_boxes:
box.draw(screen)
pg.display.flip()
clock.tick(30)
if __name__ == '__main__':
main()
pg.quit()
There are also third party modules available like pygame_textinput.
还有第三方模块可用，如pygame_textinput。
回答by Jonas De Schouwer
You can find a great module for pygame text input here .
I have been using it for a while and I really like it. A tutorial how to use it is included in the description.
However, I have added the possibility to draw a (coloured) rectangle around the text, by adding a rectand a rect_colorparameter to the __init__()function and adding
你可以在这里找到一个很棒的 pygame 文本输入模块。
我已经使用它一段时间了，我真的很喜欢它。说明中包含如何使用它的教程。
但是，我添加了在文本周围绘制（彩色）矩形的可能性，方法是向__init__()函数添加一个rect和一个rect_color参数并添加
if self.rect != None:
pygame.draw.rect(screen, self.rect_color, self.rect) #screen is my pygame display surface
to the update(self, events)function.
到update(self, events )函数。
