获取 PHP 中的完整 URL

Question

提问by DiegoP.

I use this code to get the full URL:

我使用此代码获取完整 URL：

$actual_link = 'http://'.$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF'];

The problem is that I use some masks in my .htaccess, so what we see in the URL is not always the real path of the file.

问题是我在我的中使用了一些掩码.htaccess，所以我们在 URL 中看到的并不总是文件的真实路径。

What I need is to get the URL, what is written in the URL, nothing more and nothing less—the full URL.

我需要的是获取 URL，URL 中写的内容，仅此而已——完整的 URL。

I need to get how it appears in the Navigation Bar in the web browser, and not the real path of the file on the server.

我需要了解它在 Web 浏览器的导航栏中的显示方式，而不是服务器上文件的真实路径。

Answer 1

回答by ax.

Have a look at $_SERVER['REQUEST_URI'], i.e.

看看$_SERVER['REQUEST_URI']，即

$actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";

(Note that the double quoted string syntax is perfectly correct)

（请注意，双引号字符串语法是完全正确的）

If you want to support both HTTP and HTTPS, you can use

如果你想同时支持 HTTP 和 HTTPS，你可以使用

$actual_link = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] === 'on' ? "https" : "http") . "://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";

Editor's note:using this code has security implications. The client can set HTTP_HOST and REQUEST_URI to any arbitrary value it wants.

编者注：使用此代码有安全隐患。客户端可以将 HTTP_HOST 和 REQUEST_URI 设置为它想要的任意值。

Answer 2

回答by Timo Huovinen

Short version to output link on a webpage

在网页上输出链接的简短版本

$url =  "//{$_SERVER['HTTP_HOST']}{$_SERVER['REQUEST_URI']}";

$escaped_url = htmlspecialchars( $url, ENT_QUOTES, 'UTF-8' );
echo '<a href="' . $escaped_url . '">' . $escaped_url . '</a>';

Here are some more details about the issues and edge cases of the //example.com/path/ format

以下是有关//example.com/path/ 格式的问题和边缘情况的更多详细信息

Full version

完整版本

function url_origin( $s, $use_forwarded_host = false )
{
    $ssl      = ( ! empty( $s['HTTPS'] ) && $s['HTTPS'] == 'on' );
    $sp       = strtolower( $s['SERVER_PROTOCOL'] );
    $protocol = substr( $sp, 0, strpos( $sp, '/' ) ) . ( ( $ssl ) ? 's' : '' );
    $port     = $s['SERVER_PORT'];
    $port     = ( ( ! $ssl && $port=='80' ) || ( $ssl && $port=='443' ) ) ? '' : ':'.$port;
    $host     = ( $use_forwarded_host && isset( $s['HTTP_X_FORWARDED_HOST'] ) ) ? $s['HTTP_X_FORWARDED_HOST'] : ( isset( $s['HTTP_HOST'] ) ? $s['HTTP_HOST'] : null );
    $host     = isset( $host ) ? $host : $s['SERVER_NAME'] . $port;
    return $protocol . '://' . $host;
}

function full_url( $s, $use_forwarded_host = false )
{
    return url_origin( $s, $use_forwarded_host ) . $s['REQUEST_URI'];
}

$absolute_url = full_url( $_SERVER );
echo $absolute_url;

This is a heavily modified version of http://snipplr.com/view.php?codeview&id=2734.

这是http://snipplr.com/view.php?codeview&id=2734.

URL structure:

网址结构：

scheme://username:password@domain:port/path?query_string#fragment_id

方案：//用户名：密码@域：端口/路径?query_string# fragment_id

The parts in bold will not be included by the function

粗体部分将不包含在函数中

Notes:

笔记：

This function does not include username:passwordfrom a full URL or the fragment (hash).
It will not show the default port 80 for HTTP and port 443 for HTTPS.
Only tested with http and https schemes.
The #fragment_idis not sent to the server by the client (browser) and will not be added to the full URL.
$_GETwill only contain foo=bar2for an URL like /example?foo=bar1&foo=bar2.
Some CMS's and environments will rewrite $_SERVER['REQUEST_URI']and return /example?foo=bar2for an URL like /example?foo=bar1&foo=bar2, use $_SERVER['QUERY_STRING']in this case.
Keep in mind that an URI= URL + URN, but due to popular use, URL now means both URI and URL.
You should remove HTTP_X_FORWARDED_HOSTif you do not plan to use proxies or balancers.
The specsays that the Hostheader must contain the port number unless it is the default number.

此函数不包括username:password来自完整 URL 或片段（哈希）。
它不会显示 HTTP 的默认端口 80 和 HTTPS 的端口 443。
仅使用 http 和 https 方案进行了测试。
该#fragment_id不是由客户端（浏览器）发送到服务器并不会被添加到完整的URL。
$_GET将只包含foo=bar2像/example?foo=bar1&foo=bar2.
某些 CMS 和环境将重写$_SERVER['REQUEST_URI']并返回/example?foo=bar2类似的 URL /example?foo=bar1&foo=bar2，$_SERVER['QUERY_STRING']在这种情况下使用。
请记住URI= URL + URN，但由于普遍使用，URL 现在表示 URI 和 URL。
HTTP_X_FORWARDED_HOST如果您不打算使用代理或平衡器，则应删除。
该规范说，Host标题必须包含端口号，除非它是缺省值。

Client (Browser) controlled variables:

客户端（浏览器）控制变量：

$_SERVER['REQUEST_URI']. Any unsupported characters are encoded by the browser before they are sent.
$_SERVER['HTTP_HOST']and is not always available according to comments in the PHP manual: http://php.net/manual/en/reserved.variables.php
$_SERVER['HTTP_X_FORWARDED_HOST']gets set by balancers and is not mentioned in the list of $_SERVERvariables in the PHP manual.

$_SERVER['REQUEST_URI']. 任何不受支持的字符在发送之前都由浏览器编码。
$_SERVER['HTTP_HOST']根据 PHP 手册中的注释，并不总是可用：http: //php.net/manual/en/reserved.variables.php
$_SERVER['HTTP_X_FORWARDED_HOST']由平衡器设置，$_SERVERPHP 手册的变量列表中未提及。

Server controlled variables:

服务器控制变量：

$_SERVER['HTTPS']. The client chooses to use this, but the server returns the actual value of either empty or "on".
$_SERVER['SERVER_PORT']. The server only accepts allowed numbers as ports.
$_SERVER['SERVER_PROTOCOL']. The server only accepts certain protocols.
$_SERVER['SERVER_NAME']. It is set manually in the server configuration and is not available for IPv6 according to kralyk.

$_SERVER['HTTPS']. 客户端选择使用它，但服务器返回空或“on”的实际值。
$_SERVER['SERVER_PORT']. 服务器只接受允许的数字作为端口。
$_SERVER['SERVER_PROTOCOL']. 服务器只接受某些协议。
$_SERVER['SERVER_NAME']. 它是在服务器配置中手动设置的，根据kralyk 的说法不适用于 IPv6 。

有关的：

HTTP_HOST vs. SERVER_NAME
Is Port Number Required in HTTP "Host" Header Parameter?
https://stackoverflow.com/a/28049503/175071

HTTP_HOST 与 SERVER_NAME
HTTP“主机”标头参数中是否需要端口号？
https://stackoverflow.com/a/28049503/175071

Answer 3

回答by T.Todua

Examples for: https://(www.)example.com/subFolder/myfile.php?var=blabla#555

示例： https://(www.)example.com/subFolder/myfile.php?var=blabla#555

// ======= PATHINFO ====== //
$x = pathinfo($url);
$x['dirname']       https://example.com/subFolder
$x['basename']                                    myfile.php?var=blabla#555 // Unsecure! 
$x['extension']                                          php?var=blabla#555 // Unsecure! 
$x['filename']                                    myfile

// ======= PARSE_URL ====== //
$x = parse_url($url);
$x['scheme']        https
$x['host']                  example.com
$x['path']                             /subFolder/myfile.php
$x['query']                                                  var=blabla
$x['fragment']                                                          555

//=================================================== //
//========== self-defined SERVER variables ========== //
//=================================================== //
$_SERVER["DOCUMENT_ROOT"]   /home/user/public_html
$_SERVER["SERVER_ADDR"]     143.34.112.23
$_SERVER["SERVER_PORT"]     80(or 443 etc..)
$_SERVER["REQUEST_SCHEME"]  https                                         //similar: $_SERVER["SERVER_PROTOCOL"] 
$_SERVER['HTTP_HOST']               example.com (or with WWW)             //similar: $_SERVER["ERVER_NAME"]
$_SERVER["REQUEST_URI"]                           /subFolder/myfile.php?var=blabla
$_SERVER["QUERY_STRING"]                                                var=blabla
__FILE__                    /home/user/public_html/subFolder/myfile.php
__DIR__                     /home/user/public_html/subFolder              //same: dirname(__FILE__)
$_SERVER["REQUEST_URI"]                           /subFolder/myfile.php?var=blabla
parse_url($_SERVER["REQUEST_URI"], PHP_URL_PATH)  /subFolder/myfile.php 
$_SERVER["PHP_SELF"]                              /subFolder/myfile.php

// ==================================================================//
//if "myfile.php" is included in "PARENTFILE.php" , and you visit  "PARENTFILE.PHP?abc":
$_SERVER["SCRIPT_FILENAME"] /home/user/public_html/parentfile.php
$_SERVER["PHP_SELF"]                              /parentfile.php
$_SERVER["REQUEST_URI"]                           /parentfile.php?var=blabla
__FILE__                    /home/user/public_html/subFolder/myfile.php

// =================================================== //
// ================= handy variables ================= //
// =================================================== //
//If site uses HTTPS:
$HTTP_or_HTTPS = ((!empty($_SERVER['HTTPS']) && $_SERVER['HTTPS']!=='off') || $_SERVER['SERVER_PORT']==443) ? 'https://':'http://' );            //in some cases, you need to add this condition too: if ('https'==$_SERVER['HTTP_X_FORWARDED_PROTO'])  ...

//To trim values to filename, i.e. 
basename($url)              myfile.php

//excellent solution to find origin
$debug_files = debug_backtrace();       
$caller_file = count($debug_files) ? $debug_files[count($debug_files) - 1]['file'] : __FILE__;

Notice ! ! !

注意！！！

hashtag #parts were manually used in the above example just for illustration purposes, however, server-side languages (including php) can't natively detect them (Only Javascript can do that, as hashtag is only browser/client sidefunctionality ).
DIRECTORY_SEPARATORreturns \for Windows-type hosting, instead of /.

#在上面的示例中手动使用了hashtag部分只是为了说明目的，但是，服务器端语言（包括php）无法本地检测它们（只有 Javascript 可以做到这一点，因为 hashtag 只是browser/client side功能性）。
DIRECTORY_SEPARATOR返回\Windows 类型的托管，而不是/.

For WordPress

对于 WordPress

//(let's say, if wordpress is installed in subdirectory:  http://example.com/wpdir/)
home_url()                       http://example.com/wpdir/        //if is_ssl() is true, then it will be "https"
get_stylesheet_directory_uri()   http://example.com/wpdir/wp-content/themes/THEME_NAME  [same: get_bloginfo('template_url') ]
get_stylesheet_directory()       /home/user/public_html/wpdir/wp-content/themes/THEME_NAME
plugin_dir_url(__FILE__)         http://example.com/wpdir/wp-content/themes/PLUGIN_NAME
plugin_dir_path(__FILE__)        /home/user/public_html/wpdir/wp-content/plugins/PLUGIN_NAME/

Answer 4

回答by honyovk

Here's a solution using a ternary statement, keeping the code minimal:

这是使用三元语句的解决方案，保持代码最少：

$url = "http" . (($_SERVER['SERVER_PORT'] == 443) ? "s" : "") . "://" . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'];

This is the smallest and easiest way to do this, assuming one's web server is using the standard port 443 for HTTPS.

这是执行此操作的最小和最简单的方法，假设一个人的 Web 服务器使用标准端口 443 进行HTTPS。

Answer 5

回答by Daniel Gillespie

My favorite cross platform method for finding the current URL is:

我最喜欢的用于查找当前 URL 的跨平台方法是：

$url = (isset($_SERVER['HTTPS']) ? "https" : "http") . "://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";

Answer 6

回答by HappyCoder

Simply use:

只需使用：

$uri = $_SERVER['REQUEST_SCHEME'] . '://' . $_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']

Answer 7

回答by Alex Westergaard

function full_path()
{
    $s = &$_SERVER;
    $ssl = (!empty($s['HTTPS']) && $s['HTTPS'] == 'on') ? true:false;
    $sp = strtolower($s['SERVER_PROTOCOL']);
    $protocol = substr($sp, 0, strpos($sp, '/')) . (($ssl) ? 's' : '');
    $port = $s['SERVER_PORT'];
    $port = ((!$ssl && $port=='80') || ($ssl && $port=='443')) ? '' : ':'.$port;
    $host = isset($s['HTTP_X_FORWARDED_HOST']) ? $s['HTTP_X_FORWARDED_HOST'] : (isset($s['HTTP_HOST']) ? $s['HTTP_HOST'] : null);
    $host = isset($host) ? $host : $s['SERVER_NAME'] . $port;
    $uri = $protocol . '://' . $host . $s['REQUEST_URI'];
    $segments = explode('?', $uri, 2);
    $url = $segments[0];
    return $url;
}

Note: I just made an update to Timo Huovinen's code, so you won't get any GET parameters in the URL. This URL is plain and removes things like ?hi=i&am=a&get.

注意：我刚刚更新了Timo Huovinen 的代码，因此您不会在 URL 中获得任何 GET 参数。此 URL 很简单，并删除了诸如?hi=i&am=a&get.

Example:

例子：

http://www.example.com/index?get=information

will be shown as:

将显示为：

http://www.example.com/index

This is fine unless you use GET paramaters to define some specific content, in which case you should use his code! :-)

这很好，除非你使用 GET 参数来定义一些特定的内容，在这种情况下你应该使用他的代码！:-)

Answer 8

回答by Andreas

Clear code, working in all webservers (Apache, nginx, IIS, ...):

清晰的代码，适用于所有网络服务器（Apache、nginx、IIS 等）：

$url = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] !== 'off' ? 'https' : 'http') . '://' . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'];

Answer 9

回答by Kai Noack

HTTP_HOST and REQUEST_URI must be in quotes, otherwise it throws an error in PHP 7.2

HTTP_HOST 和 REQUEST_URI 必须用引号引起来，否则在 PHP 7.2 中会抛出错误

Use:

用：

$actual_link = 'https://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];

If you want to support both HTTP and HTTPS:

如果您想同时支持 HTTP 和 HTTPS：

$actual_link = (isset($_SERVER['HTTPS']) ? 'https' : 'http').'://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];

Answer 10

回答by OzzyCzech

Here is my solution - code is inspired by Tracy Debugger. It was changed for support different server ports. You can get full current URL including $_SERVER['REQUEST_URI']or just the basic server URL. Check my function:

这是我的解决方案 - 代码的灵感来自Tracy Debugger。它已更改以支持不同的服务器端口。您可以获得完整的当前 URL，包括$_SERVER['REQUEST_URI']或仅包含基本服务器 URL。检查我的功能：

function getCurrentUrl($full = true) {
    if (isset($_SERVER['REQUEST_URI'])) {
        $parse = parse_url(
            (isset($_SERVER['HTTPS']) && strcasecmp($_SERVER['HTTPS'], 'off') ? 'https://' : 'http://') .
            (isset($_SERVER['HTTP_HOST']) ? $_SERVER['HTTP_HOST'] : (isset($_SERVER['SERVER_NAME']) ? $_SERVER['SERVER_NAME'] : '')) . (($full) ? $_SERVER['REQUEST_URI'] : null)
        );
        $parse['port'] = $_SERVER["SERVER_PORT"]; // Setup protocol for sure (80 is default)
        return http_build_url('', $parse);
    }
}

Here is test code:

下面是测试代码：

// Follow $_SERVER variables was set only for test
$_SERVER['HTTPS'] = 'off'; // on
$_SERVER['SERVER_PORT'] = '9999'; // Setup
$_SERVER['HTTP_HOST'] = 'some.crazy.server.5.name:8088'; // Port is optional there
$_SERVER['REQUEST_URI'] = '/150/tail/single/normal?get=param';

echo getCurrentUrl();
// http://some.crazy.server.5.name:9999/150/tail/single/normal?get=param

echo getCurrentUrl(false);
// http://some.crazy.server.5.name:9999/

获取 PHP 中的完整 URL

提问by DiegoP.

回答by ax.

回答by Timo Huovinen

Short version to output link on a webpage

在网页上输出链接的简短版本

Full version

完整版本

URL structure:

网址结构：

Notes:

笔记：

Client (Browser) controlled variables:

客户端（浏览器）控制变量：

Server controlled variables:

服务器控制变量：

Related:

有关的：

回答by T.Todua

For WordPress

对于 WordPress

回答by honyovk

回答by Daniel Gillespie

回答by HappyCoder

回答by Alex Westergaard

回答by Andreas

回答by Kai Noack

回答by OzzyCzech

相关推荐

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获取 PHP 中的完整 URL

提问by DiegoP.

回答by ax.

回答by Timo Huovinen

Short version to output link on a webpage

在网页上输出链接的简短版本

Full version

完整版本

URL structure:

网址结构：

Notes:

笔记：

Client (Browser) controlled variables:

客户端（浏览器）控制变量：

Server controlled variables:

服务器控制变量：

Related:

有关的：

回答by T.Todua

For WordPress

对于 WordPress

回答by honyovk

回答by Daniel Gillespie

回答by HappyCoder

回答by Alex Westergaard

回答by Andreas

回答by Kai Noack

回答by OzzyCzech

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