如何在(否定)Bash 条件中使用 OR

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时间:2020-09-18 00:45:18  来源:igfitidea点击:

How to use OR within (negative) Bash conditions

bashif-statementuser-input

提问by octosquidopus

This section of my script checks whether the distro is either Ubuntu or Arch. The problem is that I cannot figure out what to replace the ORwith to make it work. I tried -oand other suggestions from various websites without succes.

我脚本的这一部分检查发行版是 Ubuntu 还是 Arch。问题是我无法弄清楚用什么来替换OR以使其工作。我尝试-o了各种网站的其他建议,但没有成功。

if [ ! $(lsb_release -is) == "Ubuntu" OR "Arch" ]; then
 echo "Neither Ubuntu nor Arch!"
 read -p "Continue anyway(y/N)? "
 sleep 0
 [ "$REPLY" == "y" ] || exit
fi

回答by paxdiablo

You can use something like:

你可以使用类似的东西:

rel="$(lsb_release -is)"
if [[ "${rel}" != "Ubuntu" && "${rel}" != "Arch" ]]; then
   # Neither Ubuntu nor Arch
fi

回答by bash-o-logist

Use a case/esacconstruct

使用case/esac构造

case $(lsb_release -is) in
  Ubuntu|Arch ) echo "Ubuntu or Arch found";;
  * ) 
 echo "Neither Ubuntu nor Arch!"
 read -p "Continue anyway(y/N)? "
 sleep 0
 [ "$REPLY" == "y" ] || exit
 ;;
esac

回答by Sorin

Closest to your original code would be:

最接近您的原始代码是:

if [[ ! $(lsb_release -is) =~ Ubuntu|Arch ]]; then 
    echo "Neither Ubuntu nor Arch!"
    read -p "Continue anyway(y/N)? "
    sleep 0
    [ "$REPLY" == "y" ] || exit; 
fi

This uses the match operator introduced in bash 3. Also note that the above is valid in bash 3.2, prior to that you need to use quotes for the pattern.

这使用了 bash 3 中引入的匹配运算符。另外请注意,上述内容在 bash 3.2 中有效,在此之前您需要为模式使用引号。

if you don't have bash 3 you can use grep

如果你没有 bash 3 你可以使用 grep

if ! lsb_release -is| egrep -q 'Ubuntu|Arch'; then 
    echo "Neither Ubuntu nor Arch!"
    read -p "Continue anyway(y/N)? "
    sleep 0
    [ "$REPLY" == "y" ] || exit; 
fi

Note that -q is a non-standard option of grep

注意 -q 是 grep 的非标准选项

回答by octosquidopus

To answer my own question, here is a slightly longer but more flexible way of achieving the same result.

为了回答我自己的问题,这里有一个稍长但更灵活的方法来实现相同的结果。

rel="$(lsb_release -is)"
if [[ "${rel}" = "Arch" ]]; then
    echo "It's Arch"
  elif [[ "${rel}" = "Ubuntu" ]]; then
    echo "It's Ubuntu"
  else
    echo "It's Neither"
    read -p "Continue anyway(y/N)? "
    sleep 0
    [ "$REPLY" == "y" ] || exit
fi