Java Kotlin 获取类型为字符串
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Kotlin get type as string
提问by Alex Facciorusso
I can't find how to get the type of a variable (or constant) as String, like typeof(variable), with Kotlin language. How to accomplish this?
我找不到如何使用 Kotlin 语言获取变量（或常量）的类型 as String，例如typeof(variable)。如何做到这一点？
采纳答案by Lamorak
You can use one of the methods that best suits your needs:
您可以使用最适合您需求的方法之一：
val obj: Double = 5.0
System.out.println(obj.javaClass.name) // double
System.out.println(obj.javaClass.kotlin) // class kotlin.Double
System.out.println(obj.javaClass.kotlin.qualifiedName) // kotlin.Double
You can fiddle with this here.
你可以在这里摆弄这个。
回答by Rodrigo Gomes
Type Checks and Casts: 'is' and 'as'
if (obj is String) {
print(obj.length)
}
if (obj !is String) { // same as !(obj is String)
print("Not a String")
}
回答by Paulo Buchsbaum
There is a simpler way using simpleNameproperty and avoiding Kotlinprefix.
有一种更简单的方法使用simpleName属性并避免Kotlin前缀。
val lis = listOf(1,2,3)
lisis from type ArrayList. So one can use
lis来自类型ArrayList。所以可以使用
println(lis.javaClass.kotlin.simpleName) // ArrayList
or, more elegantly:
或者，更优雅地：
println(lis::class.simpleName) // ArrayList
