Javascript 打字稿重复函数实现
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Typescript Duplicate Function Implementation
提问by James B
I have defined the following two function signatures in the same Typescript class, i.e.,
我在同一个 Typescript 类中定义了以下两个函数签名，即，
public emit<T1>(event: string, arg1: T1): void {}
and
和
public emit<T1,T2>(event: string, arg1: T1, arg2: T2): void {}
However when transpiling the typescript I get the following error
但是，在转译打字稿时，我收到以下错误
error TS2393: Duplicate function implementation.
I thought you could overload functions in typescript providing the number of parameters in the function signature were different. Given that the above signatures have 2 and 3 parameters respectively, why am I getting this transpilation error?
如果函数签名中的参数数量不同，我认为您可以在打字稿中重载函数。鉴于上述签名分别有 2 个和 3 个参数，为什么我会收到此转译错误？
采纳答案by Mattias Buelens
I'm assuming your code looks like this:
我假设您的代码如下所示：
public emit<T1>(event: string, arg1: T1): void {}
public emit<T1,T2>(event: string, arg1: T1, arg2: T2): void {}
public emit(event: string, ...args: any[]): void {
// actual implementation here
}
The problem is that you have {}after the first 2 lines. This actually defines an empty implementationof a function, i.e. something like:
问题是你{}在前两行之后。这实际上定义了一个函数的空实现，例如：
function empty() {}
You only want to define a typefor the function, not an implementation. So replace the empty blocks with just a semi-colon:
您只想为函数定义类型，而不是实现。所以用分号替换空块：
public emit<T1>(event: string, arg1: T1): void;
public emit<T1,T2>(event: string, arg1: T1, arg2: T2): void;
public emit(event: string, ...args: any[]): void {
// actual implementation here
}
