bash sed 替换日期
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Sed replace date
提问by tadamhicks
So, I have looked over other questions and nothing specific seems like it can help me. I have a file that has a date variable set like mm/dd/yyyy that I would like to replace the date with.
所以，我查看了其他问题，似乎没有什么具体的问题可以帮助我。我有一个文件，它的日期变量设置为 mm/dd/yyyy，我想用它替换日期。
For example:
例如：
version.js
版本.js
//Application Version Information
app_date="7/07/2015";
...
And I would like to use sed to replace it. I actually have a shell script that replaces many things in this file, and all work except for the date. Currently what I'm trying is:
我想用 sed 来代替它。我实际上有一个 shell 脚本来替换这个文件中的很多东西，除了日期之外所有的东西都可以工作。目前我正在尝试的是：
sed -i -e 's:app_date="[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]":app_date="$(date %m/%d/%Y)":g'
But this isn't getting me the results I want. I've also tried:
但这并没有让我得到我想要的结果。我也试过：
sed -ibak 's/app_date=\"[0-9][0-9]\/[0-9][0-9]\/[0-9][0-9][0-9][0-9]\"/app_date=$(date +%m/%d/$Y)\"/g'
Neither seem to work.
两者似乎都不起作用。
Any ideas?
有任何想法吗？
Edited to add:
编辑添加：
The solution I've successfully employed is Sean Bright's with double quotes:
我成功采用的解决方案是 Sean Bright 的双引号：
sed -i -e "s:app_date=".*";:app_date="$(date +%m/%d/%Y)";:g" version.js
This works perfectly for my needs.
这非常适合我的需要。
回答by Sean Bright
I bet your script would work if the date you were matching was October 10th...
我敢打赌，如果您匹配的日期是 10 月 10 日，您的脚本会起作用……
sed -i -e 's:app_date="[0-9][0-9]*/[0-9][0-9]*/[0-9][0-9][0-9][0-9]":app_date="$(date %m/%d/%Y)":g'
Add the *s after your day and month expressions as above. [0-9][0-9]will not match 7.
*在上面的日和月表达式后添加s。[0-9][0-9]不会匹配7。
Now that I think about it, because you don't care about the date that is already in the file, most of this is unnecessary, you can simply do:
现在想想，因为你不关心文件中已经存在的日期，大部分都是不必要的，你可以简单地做：
sed -i -e 's:app_date=".*";:app_date="'$(date +%m/%d/%Y)'";:g' version.js
回答by geirha
You're using the wrong shell quotes. the command substitution $()will not be expanded inside single quotes.
您使用了错误的 shell 引号。命令替换$()不会在单引号内展开。
sed -i "/^app_date=/capp_date=\"$(date +%m/%d/%Y)\";" version.js # GNU only
Another approach, using a file editor instead of a stream editor:
另一种方法，使用文件编辑器而不是流编辑器：
ed -s version.js << EOF
/^app_date=/c
app_date="$(date +%m/%d/%Y)";
.
w
EOF
回答by keshav mainali
For replacing date with anything in Linux
用于在 Linux 中用任何内容替换日期
n=`date +%d`
cal>temp
If [$n -lt 10]
//10 is just a predction for condition
then
Sed s/"$n"/*/g temp
else
Sed s/"$n"/**/g temp
fi
// s is text substituting option //* is anything that replaces the date // g is global replacement
// s 是文本替换选项 //* 是任何替换日期的内容 // g 是全局替换
