Java：在BigDecimal中删除小数点后的零
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Java : Removing zeros after decimal point in BigDecimal
提问by Analysts
I have a program like this ,
我有一个这样的程序，
BigDecimal bd = new BigDecimal(23.086);
BigDecimal bd1= new BigDecimal(0.000);
bd = bd.setScale(2, RoundingMode.HALF_UP).stripTrailingZeros();
bd1 = bd1.setScale(2, RoundingMode.HALF_UP).stripTrailingZeros();
System.out.println("bd value::"+ bd);
System.out.println("bd1 value::"+ bd1);
I get the following output: 23.09for bdand 0.00 for bd1, but I want bd1as 0not as 0.00. Am I applying the methods correctly?
我得到以下输出：23.09forbd和 0.00 for bd1，但我想要bd1的0不是0.00. 我是否正确应用了这些方法？
采纳答案by Marcia Ong
BigDecimal bd = new BigDecimal(23.086);
BigDecimal bd1 = new BigDecimal(0.000);
bd = bd.setScale(2, RoundingMode.HALF_UP).stripTrailingZeros();
bd1 = bd1.setScale(2, RoundingMode.HALF_UP).stripTrailingZeros();
System.out.println("bd value::"+ bd); System.out.println("bd1 value::"+ bd1);
System.out.println("new way:" + bd1.intValueExact());
//OUTPUT bd value::23.09
//输出bd值::23.09
bd1 value::0.00
bd1 值::0.00
new way:0
新方式：0
回答by arshajii
回答by upog
try this
尝试这个
import java.math.BigDecimal;
import java.text.DecimalFormat;
public class calculator{
public static void main(String[] args) {
BigDecimal bd = new BigDecimal(23.086);
BigDecimal bd1= new BigDecimal(0.000);
DecimalFormat df = new DecimalFormat("0.##");
System.out.println("bd value::"+ df.format(bd));
System.out.println("bd1 value::"+ df.format(bd1));
}
}
回答by Peter Lawrey
You can do this
你可以这样做
System.out.println("bd value: " + ((bd.scale() == 0) ? bd.unscaledValue() : bd));
回答by MrSimpleMind
Simple, clean, flexible, easy-2-understand and maintain code
简单、干净、灵活、易于理解和维护的代码
(will work for doubletoo)
（会为工作double太）
DecimalFormat df = new DecimalFormat();
df.setMaximumFractionDigits(2); //Sets the maximum number of digits after the decimal point
df.setMinimumFractionDigits(0); //Sets the minimum number of digits after the decimal point
df.setGroupingUsed(false); //If false thousands separator such ad 1,000 wont work so it will display 1000
String result = df.format(bd);
System.out.println(result);
回答by Frdhsn
This method below works better IMO
下面的这种方法效果更好 IMO
bd1 = bd1.stripTrailingZeros();
System.out.println(bd1.toPlainString());
Prints:
印刷：
0
If bd1 = 1.2300 , this will print
如果 bd1 = 1.2300 ，这将打印
1.23
回答by Gondy
Let's say you have BigDecimal with value 23000.00and you want it to be 23000. You can use method stripTrailingZeros(), but it will give you "wrong" result:
假设您有一个带值的 BigDecimal23000.00并且您希望它是23000. 您可以使用 method stripTrailingZeros()，但它会给您“错误”的结果：
BigDecimal bd = new BigDecimal("23000.00");
bd.stripTrailingZeros() // Result is 2.3E+4
You can fix it by calling .toPlainString()and passing this to the BigDecimal constructor to let it handle correctly:
您可以通过调用.toPlainString()并将其传递给 BigDecimal 构造函数以使其正确处理来修复它：
BigDecimal bd = new BigDecimal("23000.00");
new BigDecimal(bd.stripTrailingZeros().toPlainString()) // Result is 23000
