java 将儒略日期转换为常规日历日期
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Convert a Julian Date to Regular Calendar Date
提问by Mark Acosta
How do I convert a 7-digit julian date into a format like MM/dd/yyy?
如何将 7 位儒略日期转换为 MM/dd/yyy 格式？
回答by scott
Found a useful site: http://www.rgagnon.com/javadetails/java-0506.html
找到了一个有用的网站：http: //www.rgagnon.com/javadetails/java-0506.html
This should do the trick:
这应该可以解决问题：
public static int[] fromJulian(double injulian) {
int jalpha,ja,jb,jc,jd,je,year,month,day;
double julian = julian + HALFSECOND / 86400.0;
ja = (int) julian;
if (ja>= JGREG) {
jalpha = (int) (((ja - 1867216) - 0.25) / 36524.25);
ja = ja + 1 + jalpha - jalpha / 4;
}
jb = ja + 1524;
jc = (int) (6680.0 + ((jb - 2439870) - 122.1) / 365.25);
jd = 365 * jc + jc / 4;
je = (int) ((jb - jd) / 30.6001);
day = jb - jd - (int) (30.6001 * je);
month = je - 1;
if (month > 12) month = month - 12;
year = jc - 4715;
if (month > 2) year--;
if (year <= 0) year--;
return new int[] {year, month, day};
}
回答by Nandan Kumar Singh
simple way is here and this will return approx 100% accurate information.
简单的方法在这里，这将返回大约 100% 准确的信息。
String getDobInfo(double doubleString){
SweDate sweDate = new SweDate(doubleString);
int year = sweDate.getYear();
int month = sweDate.getMonth();
int day = sweDate.getDay();
// getting hour,minute and sec from julian date
int hour = (int) Math.floor(sweDate.getHour());
int min = (int) Math
.round((sweDate.getHour() - Math.floor(hour)) * 60.0);
int sec = (int) (((sweDate.getHour() - Math.floor(hour)) * 60.0 - Math
.floor(min)) * 60.0);
return "DOB:(DD:MM:YY) "+day+":"+month+":"+year+" TOB:(HH:MM:SS) "+hour+":"+min+":"+sec;
}
download the Swiss Ephemeris library and enjoy coding!!!
下载瑞士星历库并享受编码！！！
回答by Tome
Starting with Java 8, this becomes a one-liner to get the LocalDate:
从 Java 8 开始，这变成了一个单线来获得LocalDate：
LocalDate.MIN.with(JulianFields.JULIAN_DAY, julianDay)
.format(DateTimeFormatter.ofPattern("MM/dd/yyyy"));
Where julianDayis your 7-digit number.
julianDay你的 7 位数字在哪里。
回答by erickson
Do you really mean a Julian date, like astronomers use? Ordinal dates, which are specified as a year (four digits) and the day within that year (3 digits), are sometimes incorrectly called Julian dates.
你真的是指天文学家使用的儒略日期吗？指定为年份（四位数）和该年中的日期（3 位数）的序数日期有时被错误地称为儒略日期。
static String formatOrdinal(int year, int day) {
Calendar cal = Calendar.getInstance();
cal.clear();
cal.set(Calendar.YEAR, year);
cal.set(Calendar.DAY_OF_YEAR, day);
Date date = cal.getTime();
SimpleDateFormat formatter = new SimpleDateFormat("MM/dd/yyyy");
return formatter.format(date);
}
This will give you the date at 00:00 local time; you may want to set the timezone on the calendars to GMT instead, depending on the application.
这将为您提供当地时间 00:00 的日期；您可能希望将日历上的时区设置为 GMT，具体取决于应用程序。
回答by Aravind Yarram
I see there are enough answers already provided. But any calendar related question is only half answered without mentioning joda-time;-). Hereis how simple it is with this library
我看到已经提供了足够的答案。但是任何与日历相关的问题都只回答了一半而没有提到joda-time;-)。这是这个库的简单之处
// setup date object for the Battle of Hastings in 1066
Chronology chrono = JulianChronology.getInstance();
DateTime dt = new DateTime(1066, 10, 14, 10, 0, 0, 0, chrono);
