Python TensorFlow 字符串:它们是什么以及如何使用它们
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TensorFlow strings: what they are and how to work with them
提问by ckorzhik
When I read file with tf.read_file
I get something with type tf.string
. Documentation says only that it is "Variable length byte arrays. Each element of a Tensor is a byte array." (https://www.tensorflow.org/versions/r0.10/resources/dims_types.html). I have no idea how to interpret this.
当我阅读文件时,tf.read_file
我得到了 type 的东西tf.string
。文档只说它是“可变长度字节数组。张量的每个元素都是一个字节数组。” (https://www.tensorflow.org/versions/r0.10/resources/dims_types.html)。我不知道如何解释这一点。
I can do nothing with this type. In usual python you can get elements by index like my_string[:4]
, but when I run following code I get an error.
我对这种类型无能为力。在通常的python中,您可以通过索引获取元素,例如my_string[:4]
,但是当我运行以下代码时,出现错误。
import tensorflow as tf
import numpy as np
x = tf.constant("This is string")
y = x[:4]
init = tf.initialize_all_variables()
sess = tf.Session()
sess.run(init)
result = sess.run(y)
print result
It says
它说
File "/usr/local/lib/python2.7/dist-packages/tensorflow/python/framework/tensor_shape.py", line 621, in assert_has_rank raise ValueError("Shape %s must have rank %d" % (self, rank)) ValueError: Shape () must have rank 1
Also I cannot convert my string to tf.float32
tensor. It is .flo
file and it has magic header "PIEH". This numpy code successfuly convert such header into number (see example here https://stackoverflow.com/a/28016469/4744283) but I can't do that with tensorflow. I tried tf.string_to_number(string, out_type=tf.float32)
but it says
我也无法将我的字符串转换为tf.float32
张量。它是.flo
文件,它有魔术头“PIEH”。此 numpy 代码成功地将此类标头转换为数字(参见此处的示例https://stackoverflow.com/a/28016469/4744283),但我无法使用 tensorflow 做到这一点。我试过了,tf.string_to_number(string, out_type=tf.float32)
但它说
tensorflow.python.framework.errors.InvalidArgumentError: StringToNumberOp could not correctly convert string: PIEH
So, what string is? What it's shape is? How can I at least get part of the string? I suppose that if I can get part of it I can just skip "PIEH" part.
那么,什么是字符串?它的形状是什么?我怎样才能至少获得一部分字符串?我想如果我能得到它的一部分,我可以跳过“PIEH”部分。
UPD: I forgot to say that tf.slice(string, [0], [4])
also doesn't work with same error.
UPD:我忘了说这tf.slice(string, [0], [4])
也不适用于相同的错误。
回答by keveman
Unlike Python, where a string can be treated as a list of characters for the purposes of slicing and such, TensorFlow's tf.string
s are indivisible values. For instance, x
below is a Tensor
with shape (2,)
whose each element is a variable length string.
与 Python 不同,在 Python 中,出于切片等目的,可以将字符串视为字符列表,而 TensorFlow 的tf.string
s 是不可分割的值。例如,x
下面是一个Tensor
with 形状,(2,)
其每个元素都是一个可变长度的字符串。
x = tf.constant(["This is a string", "This is another string"])
However, to achieve what you want, TensorFlow provides the tf.decode_raw
operator. It takes a tf.string
tensor as input, but can decode the string into any other primitive data type. For instance, to interpret the string as a tensor of characters, you can do the following :
然而,为了实现你想要的,TensorFlow 提供了tf.decode_raw
操作符。它以tf.string
张量作为输入,但可以将字符串解码为任何其他原始数据类型。例如,要将字符串解释为字符张量,您可以执行以下操作:
x = tf.constant("This is string")
x = tf.decode_raw(x, tf.uint8)
y = x[:4]
sess = tf.InteractiveSession()
print(y.eval())
# prints [ 84 104 105 115]