java 接口Java1.8中的具体方法

concrete methods in interfaces Java1.8

提问by Freak

During a discussion one of my friend tell me that concrete methods would be allowed in java 1.8 in interfacesthen at that time a question came into my mind i-e If they are allowed then How will we distinguish the methods.For example
I have two Interface Animal.javaand Pet.javaand both have same concrete method i-e eat()

在一次讨论中，我的一位朋友告诉我，concrete methods would be allowed in java 1.8 in interfaces当时我想到了一个问题，即如果允许，那么我们将如何区分这些方法。例如，
我有两个接口Animal.java，Pet.java并且它们都有相同的具体方法，即eat()

   public interfaces Animal{

        void eat(){
                System.out.println("Animal Start eating ....");
        }
   }

   public interfaces Pet{

        void eat(){
                System.out.println("Pet Start eating ....");
        }
   }

Now my Zoo.javaimplement both of these and didn't override

现在我Zoo.java实现了这两个并且没有覆盖

    public class Zoo() implements Pet , Animal{ 
             //Now name method is a part of this class
   }

Now here is my confusion.How can I call a specific method on inteface animalusing Testobject

现在这是我的困惑。如何animal使用Test对象调用接口上的特定方法

public class Demo{
        public static void main(String[] args){

                 Zoo zoo = new Zoo();
                 zoo.eat();    //What would be the output
        }
 }

Any suggestions? or is there any solution for this in java1.8 as I am unable to find its answer.

有什么建议？或者在 java1.8 中是否有任何解决方案，因为我无法找到它的答案。

采纳答案by NimChimpsky

You get a compile time error, unless you override eat in your Zoo class.

您会收到编译时错误，除非您在 Zoo 类中覆盖了eat。

java: class defaultMethods.Zoo inherits unrelated defaults for eat() from types Pet and Animal

The latest and geatest jdk is here btw. And the syntax should be

顺便说一句，最新的 jdk 在这里。语法应该是

default void eat(){
  System.out.println("Animal Start eating ....");
}