Javascript 查找对象中的键数

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时间:2020-08-23 22:55:40  来源:igfitidea点击:

Finding the number of keys in an object

javascript

提问by John Cooper

Possible Duplicate:
How to efficiently count the number of keys/properties of an object in JavaScript?

可能的重复:
如何有效地计算 JavaScript 中对象的键/属性的数量?

var values = [{
    'SPO2': 222.00000,
    'VitalGroupID': 1152,
    'Temperature': 36.6666666666667,
    'DateTimeTaken': '/Date(1301494335000-0400)/',
    'UserID': 1,
    'Height': 182.88,
    'UserName': null,
    'BloodPressureDiastolic': 80,
    'Weight': 100909.090909091,
    'TemperatureMethod': 'Oral',
    'Resprate': null,
    'HeartRate': 111,
    'BloodPressurePosition': 'Standing',
    'VitalSite': 'Popliteal',
    'VitalID': 1135,
    'Laterality': 'Right',
    'HeartRateRegularity': 'Regular',
    'HeadCircumference': '',
    'BloodPressureSystolic': 120,
    'CuffSize': 'XL'
}];

for (i=0; i < values.length; i++) {
        alert(values.length) // gives me 2. 

How can find how many keys my object has?

如何找到我的对象有多少个键?

回答by Petar Ivanov

var value = {
    'SPO2': 222.00000,
    'VitalGroupID': 1152,
    'Temperature': 36.6666666666667,
    'DateTimeTaken': '/Date(1301494335000-0400)/',
    'UserID': 1,
    'Height': 182.88,
    'UserName': null,
    'BloodPressureDiastolic': 80,
    'Weight': 100909.090909091,
    'TemperatureMethod': 'Oral',
    'Resprate': null,
    'HeartRate': 111,
    'BloodPressurePosition': 'Standing',
    'VitalSite': 'Popliteal',
    'VitalID': 1135,
    'Laterality': 'Right',
    'HeartRateRegularity': 'Regular',
    'HeadCircumference': '',
    'BloodPressureSystolic': 120,
    'CuffSize': 'XL'
};

alert(Object.keys(value).length);

回答by beardhatcode

try

尝试

Object.keys(values).length

see: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Object/keys

请参阅:https: //developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Object/keys

for compatiblity

为了兼容性

if(!Object.keys) Object.keys = function(o){
 if (o !== Object(o))
      throw new TypeError('Object.keys called on non-object');
 var ret=[],p;
 for(p in o) if(Object.prototype.hasOwnProperty.call(o,p)) ret.push(p);
 return ret;
}

or use:

或使用:

function numKeys(o){
var i=0;
for(p in o) if(Object.prototype.hasOwnProperty.call(o,p)){ i++};
return i;
}

回答by phihag

function numKeys(o) {
   var res = 0;
   for (var k in o) {
       if (o.hasOwnProperty(k)) res++;
   }
   return res;
}

or, in newer browsers:

或者,在较新的浏览器中:

function numKeys(o) {
   return Object.keys(o).length;
}

In your example, valuesis an array with one element, so you'd call numKeys(values[0])to find out.

在您的示例中,values是一个包含一个元素的数组,因此您可以致电numKeys(values[0])查找。

回答by pimvdb

You can iterate and just count:

您可以迭代并计算:

var i = 0;
for(var key in values[0]) if(values[0].hasOwnProperty(key)) i++;
// now i is amount