typescript 通过 tsc 命令打字稿：输出到单个文件，无需连接
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TypeScript via tsc command: Output to single file without concatenation
提问by Vojtěch
Is there a way of compiling single .ts file to different directory?
有没有办法将单个 .ts 文件编译到不同的目录？
The only way from the manual command of compilation to different directory is via --outcommand, but it also does concatenation of dependent files, which I don't want:
从手动编译命令到不同目录的唯一方法是通过--out命令，但它也会连接依赖文件，这是我不想要的：
--out FILE|DIRECTORY Concatenate and emit output to single file | Redirect output structure to the directory
Is there a way of redirecting the output WITHOUT concatenation of input files?
有没有办法在不连接输入文件的情况下重定向输出？
采纳答案by Alex Filatov
Unfortunately it's impossible to compile multiple *.tsfiles into one *.jswithout concatenation. Because it's impossible on API level of typescript compile options.
不幸的是，将多个*.ts文件编译成一个*.js而不串联是不可能的。因为在打字稿编译选项的 API 级别上是不可能的。
See --outoption:
查看--out选项：
DEPRECATED. Use --outFile instead.
已弃用。改用 --outFile 。
Documentation of --outFileoption:
--outFile选项文件：
Concatenate and emit output to single file. The order of concatenation is determined by the list of files passed to the compiler on the command line along with triple-slash references and imports. See output file order documentation for more details.
连接并将输出发送到单个文件。串联顺序由在命令行上传递给编译器的文件列表以及三斜杠引用和导入决定。有关更多详细信息，请参阅输出文件顺序文档。
All typescript compiler options
所有打字稿编译器选项
回答by Jeffery Grajkowski
It does one or the other. If there's no .jsextension on that file name it should assume a directory.
它有一个或另一个。如果.js该文件名没有扩展名，它应该假设一个目录。
tsc -out output.js filea.ts fileb.ts...<- output to single file output.js
tsc -out output.js filea.ts fileb.ts...<- 输出到单个文件 output.js
tsc -out output filea.ts fileb.ts...<- output individual files to dir output
tsc -out output filea.ts fileb.ts...<- 将单个文件输出到目录输出
tsc -out output/output.js filea.ts fileb.ts...<- output to single file in another directory
tsc -out output/output.js filea.ts fileb.ts...<- 输出到另一个目录中的单个文件
