javascript 根据值拆分数组
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/16018407/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Splitting array based on values
提问by Jonas
It's been a long time since I had to work on some javascript code and I'm a lot rusty.
自从我不得不处理一些 javascript 代码以来已经有很长时间了，而且我已经很生疏了。
I need to split an array like this:
我需要像这样拆分数组：
Object (
[0] => 2013-04-12
[1] => text
[2] => text
[3] => text
[4] => text
[5] => 2013-04-11
[6] => text
[7] => text
[8] => text
[9] => text
[10] => text
[11] => text
[12] => 2013-04-10
[13] => text
[14] => text
[15] => text
[16] => text
[17] => 2013-04-09
[18] => text
[19] => text
[20] => text
)
into json objects or arrays where index 0 is always the date:
进入 json 对象或数组，其中索引 0 始终是日期：
Object0 (
[0] => 2013-04-12
[1] => text
[2] => text
[3] => text
[4] => text
)
Object1 (
[0] => 2013-04-11
[1] => text
[2] => text
[3] => text
[4] => text
[5] => text
[6] => text
)
Object2 (
[0] => 2013-04-10
[1] => text
[2] => text
[3] => text
[4] => text
)
Object3 (
[0] => 2013-04-09
[1] => text
[2] => text
[3] => text
)
So as you can see, I can only use the value to figure out each new array, which can be of different sizes.
如您所见，我只能使用该值来计算每个新数组，这些数组可以具有不同的大小。
Thanks for any help.
谢谢你的帮助。
UPDATESorry I didn't publish my code in the initial question because what I had written was way too crap (and I was very ashamed). Here the code I used in the end thanks to the solution from Bangerang. Thanks everyone for your help and contributions.
更新对不起，我没有在最初的问题中发布我的代码，因为我写的东西太垃圾了（我很惭愧）。由于 Bangerang 的解决方案，我最终使用了这里的代码。感谢大家的帮助和贡献。
var events = [];
var result = [];
var j = 0;
for (var i = 0; i < tableData.length; i++){
if (/^(\d{4})-(\d{2})-(\d{2})$/.test(tableData[i])){ //Returning true if it's just numbers
j = j + 1;
events[j] = [];
events[j].push(tableData[i]);
result.push(events[j]);
} else {
events[j].push(tableData[i]);
}
}
// Then I write the json message which will be eval to use with FullCalendar.
var json_events = '[';
for (var i = 1; i <= events.length; i++){
if (typeof events[i] !== 'undefined' && events[i].length > 0) {
for (var j = 0; j < events[i].length; j++){
if(/@/.test(events[i][j])){
json_events += '{"start":"' + events[i][0] + '",';
json_events += '"textColor":"black",';
var tmp = events[i][j].split("@");
json_events += '"backgroundColor":"' + tmp[0] + '",';
var text_pattern = new RegExp(/<b>([a-z_]+)<\/b>(.+)/);
var title_desc = text_pattern.exec(tmp[1]);
json_events += '"title":"' + title_desc[1] + '",';
json_events += '"description":"' + title_desc[0] + '"';
json_events += '},';
}
}
}
}
json_events += ']';
json_events = json_events.replace("},]","}]");
回答by bangerang
Assuming that the date's is the only ones with just numbers in it you can try this:
假设日期是唯一包含数字的日期，您可以尝试以下操作：
var object = [];
var result = [];
for (var i = 0; i < objects.length; i++){
if (/^\d+$/.test(objects[i])){ //Returning true if it's just numbers
object = []
object.push(objects[i]);
result.push(object);
}else {
object.push(objects[i]);
}
}
回答by georg
basically,
基本上，
result = []
sourceArray.forEach(function(element) {
if(element looks like a date)
result.push([])
result[result.length - 1].push(element)
})
post your actual code if you want more ;)
如果您想要更多，请发布您的实际代码；)
回答by Brugnar
Currently, the work is not really complicated. You just have to go through your array, and create a new one when you encounter a date formatted cell. Until then, you fill the previous created array with the non-date encountered values. I suppose that all of the array content are string, so we will determine here the date format using a simple regex ^[0-9]{8}$
目前，这项工作并不复杂。您只需要遍历您的数组，并在遇到日期格式的单元格时创建一个新数组。在此之前，您使用非日期遇到的值填充先前创建的数组。我想所有的数组内容都是字符串，所以我们将在这里使用一个简单的正则表达式来确定日期格式^[0-9]{8}$
var result = new Array();
var date_format = /^[0-9]{8}$/;
for (var k in big_array) {
// if date format, add a new array
if (date_format.test(result[k])) {
result.push(new Array());
}
// finally, push the value in the last array
result[result.length-1].push(big_array[k]);
}
This is a really simple algorithm exercise, so i would recommend to practice more the code's writing and avoid asking next time, or at least show what you tried.
这是一个非常简单的算法练习，因此我建议多练习代码的编写，避免下次询问，或者至少展示您尝试过的内容。
Best regards.
最好的祝福。
