C++ 从文件名中删除扩展名的简单方法？
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Easy way to remove extension from a filename?
提问by Flarmar Brunjd
I am trying to grab the raw filename without the extension from the filename passed in arguments:
我试图从传入参数的文件名中获取没有扩展名的原始文件名：
int main ( int argc, char *argv[] )
{
// Check to make sure there is a single argument
if ( argc != 2 )
{
cout<<"usage: "<< argv[0] <<" <filename>\n";
return 1;
}
// Remove the extension if it was supplied from argv[1] -- pseudocode
char* filename = removeExtension(argv[1]);
cout << filename;
}
The filename should for example be "test" when I passed in "test.dat".
例如，当我传入“test.dat”时，文件名应该是“test”。
回答by Adithya Surampudi
size_t lastindex = fullname.find_last_of(".");
string rawname = fullname.substr(0, lastindex);
Beware of the case when there is no "." and it returns npos
小心没有“.”的情况。它返回 npos
回答by orlp
This works:
这有效：
std::string remove_extension(const std::string& filename) {
size_t lastdot = filename.find_last_of(".");
if (lastdot == std::string::npos) return filename;
return filename.substr(0, lastdot);
}
回答by baziorek
In my opinion it is easiest, and the most readable solution:
在我看来，这是最简单、最易读的解决方案：
#include <boost/filesystem/convenience.hpp>
std::string removeFileExtension(const std::string& fileName)
{
return boost::filesystem::change_extension(fileName, "").string();
}
回答by anhoppe
For those who like boost:
对于喜欢boost的人：
Use boost::filesystem::path::stem. It returns the filename without the last extension. So ./myFiles/foo.bar.foobar becomes foo.bar. So when you knowyou are dealing with only one extension you could do the follwing:
使用 boost::filesystem::path::stem。它返回没有最后一个扩展名的文件名。所以 ./myFiles/foo.bar.foobar 变成了 foo.bar。因此，当您知道您只处理一个扩展时，您可以执行以下操作：
boost::filesystem::path path("./myFiles/fileWithOneExt.myExt");
std::string fileNameWithoutExtension = path.stem().string();
When you have to deal with multiple extensions you might do the following:
当您必须处理多个扩展时，您可能会执行以下操作：
boost::filesystem::path path("./myFiles/fileWithMultiExt.myExt.my2ndExt.my3rdExt");
while(!path.extension().empty())
{
path = path.stem();
}
std::string fileNameWithoutExtensions = path.stem().string();
(taken from here: http://www.boost.org/doc/libs/1_53_0/libs/filesystem/doc/reference.html#path-decompositionfound in the stem section)
（取自此处：http: //www.boost.org/doc/libs/1_53_0/libs/filesystem/doc/reference.html#path-decomposition在词干部分找到）
BTW works with rooted paths, too.
顺便说一句，也适用于根路径。
回答by Shiroko
The following works for a std::string:
以下适用于 std::string：
string s = filename;
s.erase(s.find_last_of("."), string::npos);
回答by Phidelux
Since C++17 you can use std::filesystem::path::replace_extensionwith a parameter to replace the extension or without to remove it:
从 C++17 开始，您可以使用带有参数的std::filesystem::path::replace_extension来替换扩展名或不删除它：
#include <iostream>
#include <filesystem>
int main()
{
std::filesystem::path p = "/foo/bar.txt";
std::cout << "Was: " << p << std::endl;
std::cout << "Now: " << p.replace_extension() << std::endl;
}
Compileit with:
编译它：
g++ -std=c++17 -O2 -Wall -pedantic -pthread main.cpp && ./a.out
Running the resulting binary leaves you with:
运行生成的二进制文件会给你带来：
Was: "/foo/bar.txt"
Now: "/foo/bar"
回答by Baptiste Wicht
You can do this easily :
你可以很容易地做到这一点：
string fileName = argv[1];
string fileNameWithoutExtension = fileName.substr(0, fileName.rfind("."));
Note that this only work if there is a dot. You should test before if there is a dot, but you get the idea.
请注意，这仅在有点时才有效。如果有一个点，你应该先测试一下，但你明白了。
回答by Vladimir Gamalyan
More complex, but with respect to special cases (for example: "foo.bar/baz", "c:foo.bar", works for Windows too)
更复杂，但对于特殊情况（例如：“foo.bar/baz”、“c:foo.bar”，也适用于 Windows）
std::string remove_extension(const std::string& path) {
if (path == "." || path == "..")
return path;
size_t pos = path.find_last_of("\/.");
if (pos != std::string::npos && path[pos] == '.')
return path.substr(0, pos);
return path;
}
回答by Lars Fr?lich
回答by Aymen Alsaadi
Try the following trick to extract the file name from path with no extension in c++ with no external libraries in c++ :
尝试使用以下技巧从 c++ 中没有扩展名且 c++ 中没有外部库的路径中提取文件名：
#include <iostream>
#include <string>
using std::string;
string getFileName(const string& s) {
char sep = '/';
#ifdef _WIN32
sep = '\';
#endif
size_t i = s.rfind(sep, s.length());
if (i != string::npos)
{
string filename = s.substr(i+1, s.length() - i);
size_t lastindex = filename.find_last_of(".");
string rawname = filename.substr(0, lastindex);
return(rawname);
}
return("");
}
int main(int argc, char** argv) {
string path = "/home/aymen/hello_world.cpp";
string ss = getFileName(path);
std::cout << "The file name is \"" << ss << "\"\n";
}
