在 Java 中迭代 StringBuilder 的标准方法?

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/24742341/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-14 14:37:12  来源:igfitidea点击:

Standard way to iterate over a StringBuilder in Java?

javaloopsiteratorstringbuilder

提问by jmite

I was quite surprised that I couldn't find an existing questions answering this.

我很惊讶我找不到回答这个问题的现有问题。

What is the standard way to iterate over all characters in a StringBuilder in Java?

在 Java 中迭代 StringBuilder 中所有字符的标准方法是什么?

The obvious route is to just convert it to a String then use toCharArray(). The problem is, I'm dealing with thousands of unique strings, with which I do a lot of appending, and I think I'm getting memory and performance issues from having to intern them all.

显而易见的方法是将其转换为字符串,然后使用 toCharArray()。问题是,我正在处理数以千计的唯一字符串,我对这些字符串进行了很多附加操作,而且我认为我不得不将它们全部实习,从而导致内存和性能问题。

EDIT: to clarify, I'm not manually interning Strings, but my understanding was that they were automatically interned, and that if I called toStringfor a StringBuilder that they would be interned. Perhaps I have misunderstood.

编辑:澄清一下,我不是手动实习字符串,但我的理解是它们是自动实习的,如果我调用toStringStringBuilder,它们将被实习。可能我理解错了。

采纳答案by chrylis -cautiouslyoptimistic-

First off, if you're interning lots of strings, you're doing something very wrong.

首先,如果你要实习很多字符串,那你就做错了。

More generally, StringBuilderimplements CharSequence, just like String. Use an ordinary counter-based forloop and charAt().

更一般地说,StringBuilder实现CharSequence,就像String. 使用普通的基于计数器的for循环和charAt().