C++ 在 Visual Studio 2010 中将输出消息写入“输出窗口”的最简单方法？
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Simplest way to write output message to 'output window' in Visual Studio 2010?
提问by understack
I've tried OutputDebugStringfunction and most of the time I get error like :
我已经尝试过OutputDebugString函数，但大部分时间我都会收到类似的错误：
error C2664: 'OutputDebugStringA' : cannot convert parameter 1 from 'int' to 'LPCSTR'
Please suggest. Thanks.
请建议。谢谢。
回答by peter_mcc
It only accepts a string as a parameter, not an integer. Try something like
它只接受一个字符串作为参数，而不接受一个整数。尝试类似的东西
sprintf(msgbuf, "My variable is %d\n", integerVariable);
OutputDebugString(msgbuf);
For more info take a look at http://www.unixwiz.net/techtips/outputdebugstring.html
有关更多信息，请查看http://www.unixwiz.net/techtips/outputdebugstring.html
回答by Kirill V. Lyadvinsky
For debugging purposes you could use _RPTmacros.
出于调试目的，您可以使用_RPT宏。
For instance,
例如，
_RPT1( 0, "%d\n", my_int_value );
回答by Inverse
The most common way I'm aware of is the TRACEmacro:
我知道的最常见的方法是TRACE宏：
http://msdn.microsoft.com/en-us/library/4wyz8787%28VS.80%29.aspx
http://msdn.microsoft.com/en-us/library/4wyz8787%28VS.80%29.aspx
For example:
例如：
int x = 1;
int y = 16;
float z = 32.0;
TRACE( "This is a TRACE statement\n" );
TRACE( "The value of x is %d\n", x );
TRACE( "x = %d and y = %d\n", x, y );
TRACE( "x = %d and y = %x and z = %f\n", x, y, z );
回答by Jangles
I found this answer when searching the error message: https://stackoverflow.com/a/29800589
我在搜索错误消息时找到了这个答案：https: //stackoverflow.com/a/29800589
Basically, you just need put an "L" in front of your output string when using OutputDebugString:
基本上，您只需要在使用时在输出字符串前面放一个“L” OutputDebugString：
OutputDebugString(L"test\n");
OutputDebugString(L"test\n");
It worked great for me.
它对我很有用。
Edit:
编辑：
For formatting strings with data, I ended up using
为了用数据格式化字符串，我最终使用了
char buffer[100];
sprintf_s(buffer, "check it out: %s\n", "I can inject things");
OutputDebugStringA(buffer);
char buffer[100];
sprintf_s(buffer, "check it out: %s\n", "I can inject things");
OutputDebugStringA(buffer);
By no means am I an expert, I just found something that worked and moved on.
我绝不是专家，我只是找到了一些有用的东西并继续前进。
回答by Kingeh
Use:
用：
OutputDebugStringA("Some random text");
Or:
或者：
OutputDebugString("Some random text");
回答by Donotalo
To use OutputDebugString(), provide char *or const char *as parameter:
要使用 OutputDebugString()，请提供char *或const char *作为参数：
OutputDebugString("This is an output");
