如何在 URL 中传递 Javascript 变量？AJAX
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How to pass Javascript variables inside a URL? AJAX
提问by Spyros_av
i am trying to pass the values of accesstoken and pageid inside the url that i use. Any ideas how to do it correctly?
我正在尝试在我使用的 url 中传递 accesstoken 和 pageid 的值。任何想法如何正确地做到这一点？
<script type="text/javascript">
function makeUrl() {
var accesstoken = "12345679|bababashahahhahauauuaua";
var pageid = "<?php echo $page_id;?>";
$.ajax(
{
url: 'https://graph.facebook.com/?pageid/?access_token='+pageid+accesstoken,
statusCode: {......
回答by Imran
Change
改变
url: 'https://graph.facebook.com/?pageid/?access_token='+pageid+accesstoken,
to
到
url: 'https://graph.facebook.com/?pageid='+pageid+'&access_token='+accesstoken,
回答by Matt
You can also use the "data" setting. This will convert it to a query string.
您还可以使用“数据”设置。这会将其转换为查询字符串。
<script type="text/javascript">
function makeUrl() {
var accesstoken = "12345679|bababashahahhahauauuaua";
var pageid = "<?php echo $page_id;?>";
$.ajax(
{
url: 'https://graph.facebook.com/',
data: 'pageid='+pageid+'&access_token='+accesstoken
statusCode: {......
回答by KDP
'https://graph.facebook.com/?pageid='+pageid+'&access_token='+accesstoken
回答by lucasfcosta
You can create your url using:
您可以使用以下方法创建您的网址：
function makeUrl() {
var accesstoken = '12345679|bababashahahhahauauuaua';
var pageid = 'example'
return 'https://graph.facebook.com/?pageid=' + pageid + '&access_token=' + accesstoken;
}
And then pass it to your AJAX function.
然后将其传递给您的 AJAX 函数。
function doAjax(_url) {
return $.ajax({
url: _url,
type: 'GET'
});
}
doAjax(makeUrl());
And now an elegant way to handle your success callback:
现在有一种优雅的方式来处理您的成功回调：
doAjax(makeUrl()).success(function() {
// this will be executed after your successful ajax request
});
