使用替换和正则表达式在 JavaScript 中将字符串的每个单词的第一个字母大写
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Using replace and regex to capitalize first letter of each word of a string in JavaScript
提问by Daud
The following,though redundant, works perfectly :
以下虽然是多余的，但效果很好：
'leap of, faith'.replace(/([^ \t]+)/g,"$1");
'leap of, faith'.replace(/([^ \t]+)/g,"$1");
and prints "leap of, faith", but in the following :
并打印“信仰的飞跃”，但在以下内容中：
'leap of, faith'.replace(/([^ \t]+)/g,RegExp.$1);it prints "faith faith faith"
'leap of, faith'.replace(/([^ \t]+)/g,RegExp.$1);它打印“信仰信仰信仰”
As a result when I wish to capitalize each word's first character like:
因此，当我希望将每个单词的第一个字符大写时，例如：
'leap of, faith'.replace(/([^ \t]+)/g,RegExp.$1.capitalize());
'leap of, faith'.replace(/([^ \t]+)/g,RegExp.$1.capitalize());
it doesn't work. Neither does,
它不起作用。也不行，
'leap of, faith'.replace(/([^ \t]+)/g,"$1".capitalize);
'leap of, faith'.replace(/([^ \t]+)/g,"$1".capitalize);
because it probably capitalizes "$1" before substituting the group's value.
因为它可能在替换组的值之前大写“$1”。
I want to do this in a single line using prototype's capitalize() method
我想使用原型的 capitalize() 方法在一行中执行此操作
回答by Pointy
You can pass a function as the second argument of ".replace()":
你可以传递一个函数作为“.replace()”的第二个参数：
"string".replace(/([^ \t]+)/g, function(_, word) { return word.capitalize(); });
The arguments to the function are, first, the whole match, and then the matched groups. In this case there's just one group ("word"). The return value of the function is used as the replacement.
该函数的参数首先是整个匹配，然后是匹配的组。在这种情况下，只有一个组（“单词”）。函数的返回值用作替换。
