Linux 在 bash 中排序
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Sorting in bash
提问by sfactor
I have been trying to get the unique values in each column of a tab delimited file in bash. So, I used the following command.
我一直试图在 bash 中获取制表符分隔文件的每一列中的唯一值。所以，我使用了以下命令。
cut -f <column_number> <filename> | sort | uniq -c
It works fine and I can get the unique values in a column and its count like
它工作正常，我可以获得列中的唯一值及其计数
105 Linux
55 MacOS
500 Windows
What I want to do is instead of sorting by the column value names (which in this example are OS names) I want to sort them by count and possibly have the count in the second column in this output format. So It will have to look like:
我想要做的是，不是按列值名称（在本例中是操作系统名称）排序，我想按计数对它们进行排序，并且可能在此输出格式的第二列中包含计数。所以它必须看起来像：
Windows 500
MacOS 105
Linux 55
How do I do this?
我该怎么做呢？
采纳答案by paxdiablo
Use:
用：
cut -f <col_num> <filename>
| sort
| uniq -c
| sort -r -k1 -n
| awk '{print " "}'
The sort -r -k1 -nsorts in reverse order, using the first field as a numeric value. The awksimply reverses the order of the columns. You can test the added pipeline commands thus (with nicer formatting):
所述sort -r -k1 -n排序以相反的顺序，使用第一字段为数值。在awk简单地反转列的顺序。您可以因此测试添加的管道命令（使用更好的格式）：
pax> echo '105 Linux
55 MacOS
500 Windows' | sort -r -k1 -n | awk '{printf "%-10s %5d\n",,}'
Windows 500
Linux 105
MacOS 55
回答by sourcerebels
Mine:
矿：
cut -f <column_number> <filename> | sort | uniq -c | awk '{ print " "}' | sort
This will alter the column order (awk) and then just sort the output.
这将改变列顺序 (awk)，然后对输出进行排序。
Hope this will help you
希望能帮到你
回答by kartik trivikram
Using sed based on Tagged RE:
使用基于 Tagged RE 的 sed：
cut -f <column_number> <filename> | sort | uniq -c | sort -r -k1 -n | sed 's/\([0-9]*\)[ ]*\(.*\)/ /'
Doesn't produce output in a neat format though.
虽然不会以整洁的格式产生输出。
