Python 什么是“IndexError:列表索引超出范围”?

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/48753255/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-19 18:51:06  来源:igfitidea点击:

What is 'IndexError: list index out of range'?

pythonindex-error

提问by Richard Dao

This is my code:

这是我的代码:

from tkinter import messagebox, simpledialog, Tk

def is_even(number):
    return number % 2 == 0

def get_even_letters(message):
    even_letters = []
    for counter in range(0, len(message)):
        if is_even(counter):
            even_letters.append(message[counter])
        return even_letters

def get_odd_letters(message):
    odd_letters = []
    for counter in range(0, len(message)):
        if not is_even(counter):
            odd_letters.append(message[counter])
    return odd_letters

def swap_letters(message):
    letter_list = []
    if not is_even(len(message)):
        message = message + 'x'
    even_letters = get_even_letters(message)
    odd_letters = get_odd_letters(message)
    for counter in range(0, int(len(message)/2)):
        letter_list.append(odd_letters[counter])
        letter_list.append(even_letters[counter])
    new_message = ''.join(letter_list)
    return new_message


def get_task():
    task = simpledialog.askstring('Task', 'Do you want to encrypt or decrypt?')
    return task

def get_message():
    message = simpledialog.askstring('Message', 'Enter the secret message')
    return message
root = Tk()

while True:
    task = get_task()
    if task == 'encrypt':
        message = get_message()
        encrypted = swap_letters(message)
        messagebox.showinfo('Ciphertext of the secret message is:', encrypted)
    elif task == 'decrypt':
        message = get_message()
        decrypted = swap_letters(message)
        messagebox.showinfo('Plain text of the secret message is: ', decrypted)
    else:
        break
root.mainloop()

Currently using IDLE, Python 3.6.3. Whenever I run the program, the first prompt works, 'encrypt', but when I get to the 'Enter the secret message' prompt, if I type anything with more than 2 letters, it gives me the error:

目前使用空闲,Python 3.6.3。每当我运行程序时,第一个提示都会起作用,“加密”,但是当我进入“输入秘密消息”提示时,如果我输入的任何内容超过 2 个字母,就会出现错误:

Traceback (most recent call last):
  File "/Users/richarddao/Documents/secret_message.py", line 46, in <module>
    encrypted = swap_letters(message)
  File "/Users/richarddao/Documents/secret_message.py", line 28, in swap_letters
    letter_list.append(even_letters[counter])
IndexError: list index out of range

What is IndexError: list index out of range? How do I fix this?

什么是 IndexError:列表索引超出范围?我该如何解决?

回答by Qwerty

Index Error: List index out of rangemeans you are trying to get an item in a list that doesn't exist.

Index Error: List index out of range意味着您正在尝试获取不存在的列表中的项目。

For Example, I have this list:

例如,我有这个列表:

["a","b","c"]

["a","b","c"]

So a is the 0th item, b is the 1st, and c is the 2nd.

所以a是第0项,b是第1项,c是第2项。

I can get b by doing ["a","b","c"][1]because it is the first item and I am calling for the first item with [1].

我可以通过这样做得到 b,["a","b","c"][1]因为它是第一个项目,我用 [1] 调用第一个项目。

An index error is what would happen if I tried to do this:

如果我尝试这样做会发生索引错误:

["a","b","c"][4]

["a","b","c"][4]

There is no 4th item, so it errors.

没有第四项,所以它出错了。

回答by Richard Dao

So, uh it turns out it was a really simple answer... I needed to remove an indent from Line 11.

所以,呃事实证明这是一个非常简单的答案......我需要从第 11 行中删除一个缩进。

return even_letters

RIP. Thanks for everyone's explanation.

撕裂。谢谢大家的解释。