java 如何在 JSON 字符串中的日期时间值中转义冒号
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How to escape a colon inside a datetime value in a JSON string
提问by user2475664
I need to instantiate a JSONObject with a string that I receive from an external source. The string contains a datetime value, which in turn contains a colon. When I try to create an instance of the JSONObject, I get an error, it looks like JSON does not like the colon in the middle of the date time value.
我需要使用从外部源接收的字符串实例化 JSONObject。该字符串包含一个日期时间值，该值又包含一个冒号。当我尝试创建 JSONObject 的实例时，出现错误，看起来 JSON 不喜欢日期时间值中间的冒号。
Here is a code snippet:
这是一个代码片段：
@Test
public void testGetDate()
{
String jsonStr = "{\"sDate\":2013-06-15T09:30:09+0000}";
try
{
JSONObject jsonObject = new JSONObject(jsonStr);
System.out.println(jsonObject.get("sDate"));
} catch (JSONException e)
{
e.printStackTrace();
}
}
The error I get is:
我得到的错误是：
org.json.JSONException: Expected a ',' or '}' at 23 [character 24 line 1]
Has anyone encountered this ? Is there some way to escape the colon?
有没有人遇到过这个？有没有办法摆脱结肠？
采纳答案by willwest
If you surround your date/time object in double quotes, it should accept it.
如果您用双引号将日期/时间对象括起来，它应该接受它。
This should work:
这应该有效：
String jsonStr = "{\"sDate\":\"2013-06-15T09:30:09+0000\"}";
回答by Tom G
Strings are required to be quoted in JSON:
字符串需要在 JSON 中引用：
string
""
" chars "
Your snippet is invalid, which is why the exception is thrown. You must surround the string value with double quotes.
您的代码段无效，这就是抛出异常的原因。您必须用双引号将字符串值括起来。
