xcode Xcode中指针和整数（id和int）的比较
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时间：2020-09-15 02:08:51 来源:igfitidea点击:
Comparison between pointer and integer(id and int) in Xcode
提问by user1765037
While running this
在运行这个
if([SUPApplication ConnectionStatus]==[SUPConnectionStatus_DISCONNECTED])
{......
......}
we are getting a warning like "comparison between pointer and integer(id and int)" Why like that.Is there any functions to parse both into same datatype.
我们收到了一个警告，比如“指针和整数（id 和 int）之间的比较”为什么会这样。是否有任何函数可以将两者解析为相同的数据类型。
回答by Dimitar Marinov
Try to cast them:
尝试投射它们：
if((int)[SUPApplication ConnectionStatus]== (int)SUPConnectionStatus_DISCONNECTED)
回答by Yuliani Noriega
Try making them both into NSNumbersand then compare there values
尝试将它们都放入NSNumbers然后比较它们的值
if ([[NSNumber numberWithInt:[SUPApplication ConnectionStatus]] isEqualToNumber:[NSNumber numberWithInt:SUPConnectionStatus_DISCONNECTED]])
{
....
}
