PHP foreach 循环使用数组数组中的值填充下拉列表
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PHP foreach loop to populate dropdown list with values from an array of arrays
提问by Mr. B
I have an array of an arrayscreated using the following code. I'm trying to get this to loop through and populate a dropdown list.
我有一个使用以下代码创建的数组数组。我试图让它循环并填充下拉列表。
$names = $db->fetchAll("select `name` from `classes`");
This is what is stored in the $names variable.
这是存储在 $names 变量中的内容。
Array ( [0] => Array ( [name] => Web Design ) [1] => Array ( [name] => Art History ) [2] => Array ( [name] => Gym ) [3] => Array ( [name] => English ) [4] => Array ( [name] => Biology ) [5] => Array ( [name] => 3D Animation ) [6] => Array ( [name] => Tech Disc ) [7] => Array ( [name] => Math ) [8] => Array ( [name] => Dance ) [9] => Array ( [name] => Video Production ) [10] => Array ( [name] => Home Ec ) [11] => Array ( [name] => Government ) [12] => Array ( [name] => Physics ) )
Array ( [0] => Array ( [name] => 网页设计 ) [1] => Array ( [name] => 艺术史 ) [2] => Array ( [name] => Gym ) [3] = > Array ( [name] => English ) [4] => Array ( [name] => Biology ) [5] => Array ( [name] => 3D Animation ) [6] => Array ( [name] = > Tech Disc ) [7] => Array ( [name] => Math ) [8] => Array ( [name] => Dance ) [9] => Array ( [name] => Video Production ) [10] => Array ( [name] => Home Ec ) [11] => Array ( [name] => Government) [12] => Array ( [name] => Physics ) )
I have this dropdown list created and it work, but it is hand coded for each value in the array. I want to modify this so it 'loops' through all results in the array to create the dropdown.
我创建了这个下拉列表并且它可以工作，但它是为数组中的每个值手动编码的。我想修改它，以便它“循环”数组中的所有结果以创建下拉列表。
<label for="per1"></label>
<select name="per1" id="per1">
<option selected="selected">Choose one</option>
<option value="<?php echo $names[0]['name'];?>"><?php echo $names[0]['name'];?></option>
<option value="<?php echo $names[1]['name'];?>"><?php echo $names[1]['name'];?></option>
<option value="<?php echo $names[2]['name'];?>"><?php echo $names[2]['name'];?></option>
<option value="<?php echo $names[3]['name'];?>"><?php echo $names[3]['name'];?></option>
<option value="<?php echo $names[4]['name'];?>"><?php echo $names[4]['name'];?></option>
<option value="<?php echo $names[5]['name'];?>"><?php echo $names[5]['name'];?></option>
<option value="<?php echo $names[6]['name'];?>"><?php echo $names[6]['name'];?></option>
<option value="<?php echo $names[7]['name'];?>"><?php echo $names[7]['name'];?></option>
<option value="<?php echo $names[8]['name'];?>"><?php echo $names[8]['name'];?></option>
<option value="<?php echo $names[9]['name'];?>"><?php echo $names[9]['name'];?></option>
<option value="<?php echo $names[10]['name'];?>"><?php echo $names[10]['name'];?></option>
<option value="<?php echo $names[11]['name'];?>"><?php echo $names[11]['name'];?></option>
<option value="<?php echo $names[12]['name'];?>"><?php echo $names[12]['name'];?></option>
</select>
Can someone please help?
有人可以帮忙吗？
回答by Josh from Qaribou
This solution works for current PHP versions.Simple case of using a foreach:
此解决方案适用于当前的 PHP 版本。使用 foreach 的简单案例：
<select name="per1" id="per1">
<option selected="selected">Choose one</option>
<?php
foreach($names as $name) { ?>
<option value="<?= $name['name'] ?>"><?= $name['name'] ?></option>
<?php
} ?>
</select>
This solution works for older PHP versions.Simple case of using a foreach:
此解决方案适用于较旧的 PHP 版本。使用 foreach 的简单案例：
<select name="per1" id="per1">
<option selected="selected">Choose one</option>
<?php
foreach($names as $name) { ?>
<option value="<?php echo $name['name'] ?>"><?php echo $name['name'] ?></option>
<?php
} ?>
</select>
回答by ??q?? zo???
i think this is enough
我觉得这就够了
foreach($names as $key =>$value)
{?>
<option value="<?=$value['name']?>"><?=$value['name']?></option>
<?php }
回答by N.M.N
Go for for each loop to avoid these much coding.
为每个循环寻找代码以避免这么多的编码。
<?php
foreach($names as $nameIndex=>$nameVal){ ?>
<option value=$nameVal['name']?>"><?=$nameVal['name']?> </option>
<?php } ?>
