javascript Jquery循环遍历表中没有第一行的所有行
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Jquery loop through all the rows in a table without first row
提问by dev1234
I need to loop through all rows for a particular table, and I have done it as below. At one point, I need to remove the matching table row. I couldn't figure out how to skip the first row and loop through all others. My code below is looping through all tr's.
我需要遍历特定表的所有行，我已经完成了如下操作。有一次，我需要删除匹配的表格行。我不知道如何跳过第一行并遍历所有其他行。我下面的代码循环遍历所有 tr。
$('#tbl_dynamic_call_dates > tbody > tr').each(
function() {
console.log($(this).find(\'td:first\').text());
if($.inArray($(this).find(\'td:first\').text(),array) == -1){
$(this).remove();
}
回答by DrColossos
$('#tbl_dynamic_call_dates > tbody > tr').not(":first"). [....]
to get everything BUT the first
得到一切但第一个
$('#tbl_dynamic_call_dates > tbody > tr:first'). [...]
or
或者
$('#tbl_dynamic_call_dates > tbody > tr').first(). [...]
to only get the first
只得到第一个
回答by Reinstate Monica Cellio
Change your selector to this...
将您的选择器更改为此...
$('#tbl_dynamic_call_dates > tbody > tr:not(:first)')
回答by pala?н
You can do this using the :gt() Selectorlike:
您可以使用以下方法执行此操作:gt() Selector：
$('#tbl_dynamic_call_dates > tbody > tr:gt(0)').each(function() {...});
回答by David says reinstate Monica
$('#tbl_dynamic_call_dates > tbody > tr:gt(0)').each(/*...*/);
Or:
或者：
$('#tbl_dynamic_call_dates > tbody > tr').first().siblings().each(/*...*/);
