仅按python中的第一个空格拆分字符串
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Split a string only by first space in python
提问by bazinga
I have string for example: "238 NEO Sports". I want to split this string only at the firstspace. The output should be ["238","NEO Sports"].
我有字符串，例如："238 NEO Sports". 我只想在第一个空格处拆分此字符串。输出应该是["238","NEO Sports"].
One way I could think of is by using split()and finally merging the last two strings returned. Is there a better way?
我能想到的一种方法是使用split()并最终合并返回的最后两个字符串。有没有更好的办法？
采纳答案by Avinash Raj
Just pass the count as second parameter to str.splitfunction.
只需将计数作为第二个参数传递给str.split函数。
>>> s = "238 NEO Sports"
>>> s.split(" ", 1)
['238', 'NEO Sports']
回答by wim
RTFM: str.split(sep=None, maxsplit=-1)
RTFM： str.split(sep=None, maxsplit=-1)
>>> "238 NEO Sports".split(None, 1)
['238', 'NEO Sports']
回答by Haresh Shyara
Use string.split()
使用 string.split()
string = "238 NEO Sports"
print string.split(' ', 1)
Output:
输出：
['238', 'NEO Sports']
