spring 使用不同的参数为相同的 url 模式创建两种方法
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create two method for same url pattern with different arguments
提问by Vikas Singh
I have scenario where one url "serachUser" may come with two different value (request parameter) userId or UserName.
我有一个场景，其中一个 url“serachUser”可能带有两个不同的值（请求参数）userId 或 UserName。
so for this I have created two methods
所以为此我创建了两种方法
public String searchUserById(@RequestParam long userID, Model model)
public ModelAndView searchUserByName(@RequestParam String userName)
But i am getting Ambiguous mapping found exception. Spring has any way to handle this situation.
但是我发现了模糊映射发现异常。Spring 有办法处理这种情况。
回答by kryger
You can use the paramsparameter to filter by HTTP parameters. In your case it would be something like:
您可以使用该params参数按 HTTP 参数进行过滤。在你的情况下，它会是这样的：
@RequestMapping(value = "/searchUser", params = "userID")
public String searchUserById(@RequestParam long userID, Model model) {
// ...
}
@RequestMapping(value = "/searchUser", params = "userName")
public ModelAndView searchUserByName(@RequestParam String userName) {
// ...
}
