bash 是否有 shell 命令递归地授予目录和文件的权限？
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Is there a shell command to recursively give permission to directories and files?
提问by Abs
Can someone please give me a recursive command that will go through a directory and make all normal files permission 644 and all sub directories 755?
有人可以给我一个递归命令，该命令将遍历一个目录并使所有普通文件的权限为 644，所有子目录的权限为 755？
I am really getting tired of doing this manually every time I have to install something on my host. I don't know enough BASH (Shell?) command to do this.
每次必须在主机上安装某些东西时，我真的厌倦了手动执行此操作。我不知道足够的 BASH（Shell？）命令来执行此操作。
回答by ypnos
There is X option for that.
有 X 选项。
chmod a+X * -R
This will give execute bit only to directories, not files. To set 644, 755, respectively with one command, use:
这只会为目录而不是文件提供执行位。用一个命令分别设置 644、755，使用：
chmod a=rX,u+w <files/dirs> -R
回答by Kaarel
First line changes file permissions, and the second changes directory permissions in the active directory and its subdirectories.
第一行更改文件权限，第二行更改活动目录及其子目录中的目录权限。
find . -type f -print0 | xargs -0 chmod 644
find . -type d -print0 | xargs -0 chmod 755
回答by sth
Using symbolic mode names instead of raw numeric permissions:
使用符号模式名称而不是原始数字权限：
chmod -R u=rwX,go=rX somedir
The Xpermission flag only sets directories or already executable files as executable, the -Rflag means "recursive" and applies the permissions to all the contents of the somedir.
该X许可标志仅设置目录或已可执行文件为可执行，该-R标志表示“递归”，并应用权限的所有内容somedir。
回答by J?rg W Mittag
No, there is no command to recursively change the permissions. If there were such a command, it would violate the Unix mantra: Do One Thing And Do It Well.
不，没有递归更改权限的命令。如果有这样的命令，那就违背了 Unix 的口头禅：Do One Thing And Do It Well。
However, there are twocommands: one for recursing (find), and one for changing permissions (chmod).
但是，有两个命令：一个用于递归 ( find)，另一个用于更改权限 ( chmod)。
So, the magic command line is:
所以，神奇的命令行是：
find . -type d -exec chmod 0755 '{}' + -or -type f -exec chmod 0644 '{}' +
