java 从时间戳获取日期
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get date from timestamp
提问by sweety
My code is:
我的代码是：
import java.text.*;
import java.util.Date;
public class DateEx {
public static void main(String[] args) {
//String valueFromDB = "2012/06/06 00:00:00";
String valueFromDB = "2012-12-31 00:00:00.0";
Date d = new Date(valueFromDB);
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy");
String dateWithoutTime = sdf.format(d);
System.out.println("sdf.format(d) " + dateWithoutTime);
}
}
It works for "2012/06/06 00:00:00"and I need to pass "2012-12-31 00:00:00.0"it is showing illegal argument. May be because I have use "-"in date or because of timestamp fraction second. I need date in dd-mm-yyyyformat.
它适用于"2012/06/06 00:00:00"我需要通过"2012-12-31 00:00:00.0"它显示非法参数。可能是因为我使用"-"了日期或因为时间戳分数秒。我需要dd-mm-yyyy格式的日期。
回答by arajshree
This may be helpful.
这可能会有所帮助。
long dateTimeStamp = 1487269800;
Timestamp stamp = new Timestamp(dateTimeStamp*1000);
Date changeDate = new Date(stamp.getTime());
Output:
输出：
Date :Fri Feb 17 00:00:00 IST 2017
回答by Steven You
In order to parse a string to Date type, use the code below:
要将字符串解析为 Date 类型，请使用以下代码：
DateFormat formatter;
Date date;
formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
date = (Date)formatter.parse("2012-12-31 00:00:00");
回答by JHS
Try this -
试试这个 -
SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss.S");
String valueFromDB = "2012-12-31 00:00:00.0";
Date d1 = sdf1.parse(valueFromDB);
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy");
String dateWithoutTime = sdf.format(d1);
System.out.println("sdf.format(d) " + dateWithoutTime);
