从 PHP 下拉框中获取 Selected 值
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Get the Selected value from the Drop down box in PHP
提问by Subash
I am populating a Drop Down Box using the following code.
我正在使用以下代码填充下拉框。
<select id="select_catalog">
<?php
$array_all_catalogs = $db->get_all_catalogs();
foreach($array_all_catalogs as $array_catalog){?>
<option value="<?= $array_catalog['catalog_key'] ?>"><?= array_catalog['catalog_name'] ?></option>
Now how can I get the selected option value using PHP(I have the code to get the selected item using Javascriptand jQuery) because I want the selected value to perform a query in database.
现在如何使用PHP（我有使用Javascript和获取所选项目的代码）获取所选选项值，jQuery因为我希望所选值在数据库中执行查询。
Any help will be much appreciated. Thank you very much...
任何帮助都感激不尽。非常感谢...
回答by Manuel
You need to set a name on the <select>tag like so:
您需要在<select>标签上设置一个名称，如下所示：
<select name="select_catalog" id="select_catalog">
You can get it in php with this:
您可以通过以下方式在 php 中获取它：
$_POST['select_catalog'];
回答by Aleski
Couldnt you just pass the a name attribute? And wrap it in a form?
你不能只传递一个名称属性吗？并将其包装成表格？
<form id="form" action"do_stuff.php" method="post">
<select id="select_catalog" name="select_catalog_query">
<?php <<<INSERT THE SELECT OPTION LOOP >>> ?>
</select>
</form>
And then look for $_POST['select_catalog_query']?
然后找$_POST['select_catalog_query']？
回答by Shashank Saxena
Posting it from my project.
从我的项目中发布它。
<select name="parent" id="parent"><option value="0">None</option>
<?php
$select="select=selected";
$allparent=mysql_query("select * from tbl_page_content where parent='0'");
while($parent=mysql_fetch_array($allparent))
{?>
<option value="<?= $parent['id']; ?>" <?php if( $pageDetail['parent']==$parent['id'] ) { echo($select); }?>><?= $parent['name']; ?></option>
<?php
}
?></select>
回答by Iso
You have to give a nameattribute on your <select />element, and then use it from the $_POSTor $_GET(depending on how you transmit data) arrays in PHP. Be sure to sanitize user input, though.
您必须name在您的<select />元素上提供一个属性，然后从PHP 中的$_POSTor $_GET（取决于您传输数据的方式）数组中使用它。不过，一定要清理用户输入。
