具有多个“server_name”条目的 nginx“server”指令：总是第一个传递给 PHP 的 $_SERVER['SERVER_NAME']
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nginx "server" directive with multiple "server_name" entries: always first one is passed to PHP's $_SERVER['SERVER_NAME']
提问by Paolo
My configuration file has a serverdirective block that begins with...
我的配置文件有一个server以...开头的指令块
server {
server_name www.example1.com www.example2.com www.example3.com;
...in order to allow the site to be accessed with different domain names.
...为了允许使用不同的域名访问该站点。
However PHP's $_SERVER['SERVER_NAME']always returns the first entry of server_name, in this case http://www.example1.com
但是 PHP$_SERVER['SERVER_NAME']总是返回 的第一个条目server_name，在这种情况下http://www.example1.com
So I have no way from the PHP code to know which domain the user used to access the site.
所以我无法从 PHP 代码知道用户使用哪个域访问该站点。
Is there any way to tell nginx/fastcgi to pass the real domain name used to access the site?
有什么办法可以告诉nginx/fastcgi传递用于访问站点的真实域名吗？
The only solution I've found so far is to repeat the entire serverblock for each domain with a distinct server_nameentry but obviously I'm looking for a better one.
到目前为止，我找到的唯一解决方案是server使用不同的server_name条目为每个域重复整个块，但显然我正在寻找更好的解决方案。
回答by Tan Hong Tat
Set SERVER_NAMEto use $hostin your fastcgi_paramsconfiguration.
设置SERVER_NAME为$host在您的fastcgi_params配置中使用。
fastcgi_param SERVER_NAME $host;
Source: http://nginx.org/en/docs/http/ngx_http_fastcgi_module.html#fastcgi_param
来源：http: //nginx.org/en/docs/http/ngx_http_fastcgi_module.html#fastcgi_param
回答by Sjon
This is intended and the proper solution is to use $_SERVER['HTTP_HOST']in your code instead.
这是有意的，正确的解决方案是$_SERVER['HTTP_HOST']在您的代码中使用。
You should interpret SERVER_NAMEas a verifiedserver-name, and HTTP_HOSTas user-input which can be modified quite easily, and thus shouldn't be trusted.
您应该将其解释SERVER_NAME为经过验证的服务器名称，以及HTTP_HOST可以很容易修改的用户输入，因此不应被信任。
