Laravel 5.5 - 检查字符串是否包含准确的单词
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Laravel 5.5 - Check if string contains exact words
提问by Wonka
In laravel, I have a $stringand a $blacklistArray
在laravel中，我有一个$string和一个$blacklistArray
$string = 'Cassandra is a clean word so it should pass the check';
$blacklistArray = ['ass','ball sack'];
$contains = str_contains($string, $blacklistArray); // true, contains bad word
The result of $containsis true, so this will be flagged as containing a black list word (which is not correct). This is because the name below partially contains ass
的结果$contains为真，因此这将被标记为包含黑名单单词（这是不正确的）。这是因为下面的名称部分包含ass
Cassandra
Ç屁股安德拉
However, this is a partial match and Cassandrais not a bad word, so it should not be flagged. Only if a word in the string is an exact match, should it be flagged.
然而，这是一个部分匹配，Cassandra不是一个坏词，所以它不应该被标记。仅当字符串中的单词完全匹配时，才应对其进行标记。
Any idea how to accomplish this?
知道如何做到这一点吗？
采纳答案by Diego Cespedes
$blacklistArray = array('ass','ball sack');
$string = 'Cassandra is a clean word so it should pass the check';
$matches = array();
$matchFound = preg_match_all(
"/\b(" . implode($blacklistArray,"|") . ")\b/i",
$string,
$matches
);
// if it find matches bad words
if ($matchFound) {
$words = array_unique($matches[0]);
foreach($words as $word) {
//show bad words found
dd($word);
}
}
回答by set0x
Docs: https://laravel.com/docs/5.5/helpers#method-str-contains
文档：https: //laravel.com/docs/5.5/helpers#method-str-contains
The str_containsfunction determines if the given string contains the given value:
该str_contains函数确定给定的字符串是否包含给定的值：
$contains = str_contains('This is my name', 'my');
You may also pass an array of values to determine if the given string contains any of the values:
您还可以传递一组值来确定给定的字符串是否包含任何值：
$contains = str_contains('This is my name', ['my', 'foo']);
回答by Tpojka
str_contains()works with strings - not with arrays, but you can loop it:
str_contains()适用于字符串 - 不适用于数组，但您可以循环它：
$string = 'Cassandra is a clean word so it should pass the check';
$blacklistArray = ['ass','ball sack'];
$flag = false;
foreach ($blacklistArray as $k => $v) {
if str_contains($string, $v) {
$flag = true;
break;
}
}
if ($flag == true) {
// someone was nasty
}
