xcode 禁用 UISearchBar
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Disable UISearchBar
提问by Tom
I have a -as I hope- very simple question: how to disable an UISearchBar in IOS5 to avoid user interaction? I can't find setEnabled or something like this...
我有一个 - 正如我希望的 - 非常简单的问题：如何在 IOS5 中禁用 UISearchBar 以避免用户交互？我找不到 setEnabled 或类似的东西...
Thanks!
谢谢！
回答by Conrad Shultz
Have you tried:
你有没有尝试过：
[searchBar setUserInteractionEnabled:NO];
?
?
回答by flizit
In addition to setting user interaction, I also adjusted the alpha value as well, to make the appearance unique.
除了设置用户交互，我还调整了 alpha 值，使外观独一无二。
searchbar.alpha = .75;
回答by Mazen Kasser
Try this
尝试这个
// Normal
self.searchDisplayController.searchBar.userInteractionEnabled = YES;
self.searchDisplayController.searchBar.translucent = YES;
self.searchDisplayController.searchBar.searchBarStyle = UISearchBarStyleDefault;
self.searchDisplayController.searchBar.backgroundColor = [UIColor clearColor];
// Faded out
self.searchDisplayController.searchBar.userInteractionEnabled = NO;
self.searchDisplayController.searchBar.translucent = NO;
self.searchDisplayController.searchBar.searchBarStyle = UISearchBarStyleMinimal;
self.searchDisplayController.searchBar.backgroundColor = [UIColor lightGrayColor];
回答by CodeBender
An extension for Swift 4 that provides functions to enable and disable the UISearchBar. Feel free to adjust the alpha value as you see fit, since color schemes in use can impact the result.
Swift 4 的扩展，提供启用和禁用UISearchBar. 随意调整您认为合适的 alpha 值，因为使用的配色方案会影响结果。
extension UISearchBar {
func enable() {
isUserInteractionEnabled = true
alpha = 1.0
}
func disable() {
isUserInteractionEnabled = false
alpha = 0.5
}
}
Then to disable the searchBar:
然后禁用搜索栏：
searchBar.disable()
To enable:
启用：
searchBar.enable()
回答by pableiros
For Swift 3:
对于 Swift 3：
self.searchController.searchBar.isUserInteractionEnabled = true
Or if you want to still detect user interaction you can do this to disable the UITextFieldinside the UISearchBar:
或者，如果您仍想检测用户交互，您可以执行此操作以禁用UITextField内部UISearchBar：
(self.searchController.searchBar.value(forKey: "searchField") as! UITextField).isEnabled = false
