json 客户端发送的请求语法错误 ().+Spring , RESTClient
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The request sent by the client was syntactically incorrect ().+Spring , RESTClient
提问by Chandrasekar
I am working with Spring MVC using JSON objects. while I am tring to send JSON Object from RESTClient, I am getting
我正在使用 JSON 对象使用 Spring MVC。当我试图从 RESTClient 发送 JSON 对象时，我得到了
HTTP Status 400 - The request sent by the client was syntactically incorrect ().
HTTP 状态 400 - 客户端发送的请求在语法上不正确 ()。
This is my controller
这是我的控制器
ObjectMapper mapper=new ObjectMapper();
@RequestMapping(value = "/addTask", method = RequestMethod.GET)
public ModelAndView addTask(@RequestParam("json") String json) throws JsonParseException, JsonMappingException, IOException
{
System.out.println("Json object from REST : "+json);
Task task=(Task) mapper.readValue(json, Task);
service.addService(task);
return new ModelAndView("Result");
}
My request URL : http://localhost:8080/Prime/addTask
我的请求网址： http://localhost:8080/Prime/addTask
My Json Object :
我的 Json 对象：
{"taskName":"nothing","taskId":1234,"taskDesc":"nothing doing"}
{"taskName":"nothing","taskId":1234,"taskDesc":"什么都不做"}
Also i tried specifying "Content-Type: application/json" in RESTClient but still am getting the same error
我还尝试在 RESTClient 中指定“Content-Type: application/json”，但仍然遇到相同的错误
采纳答案by Kris
Try this
尝试这个
Change
改变
@RequestParam("json") String json
To
到
@RequestBody Task task
If you are not interested in POST method you can try this
如果你对 POST 方法不感兴趣，你可以试试这个
change your Controller method from
改变你的控制器方法
@RequestMapping(value = "/addTask", method = RequestMethod.GET)
public ModelAndView addTask(@RequestParam("json") String json)
to
到
@RequestMapping(value = "/addTask/{taskName}/{taskId}/{taskDesc}", method = RequestMethod.GET)
public ModelAndView addTask(@RequestParam("taskName") String taskName,
@RequestParam("taskId") String taskId,@RequestParam("taskDesc") String taskDesc)
and change your URL to
并将您的网址更改为
http://localhost:8080/Prime/addTask/mytask/233/testDesc
回答by Ben Iggulden
I ran into a similar situation using a JSON string in the request body recently, and using a very similar Spring setup as yours. In my case I wasn't specifying a String parameter and deserialising it myself though, I was letting Spring do that:
我最近在请求正文中使用 JSON 字符串遇到了类似的情况，并使用了与您非常相似的 Spring 设置。在我的情况下，我没有指定 String 参数并自己反序列化它，但我让 Spring 这样做：
@RequestMapping(value = "/myService/{id}", method = RequestMethod.POST)
@ResponseBody
public void myService(@PathVariable(value = "id") Long id, @RequestBody MyJsonValueObject request) {
..
}
I was getting an HTTP error 400 "The request sent by the client was syntactically incorrect" response. Until I realised that there wasn't a default constructor on the @RequestBody MyJsonValueObjectso there were problems deserialising it. That problem presented in this way though.
我收到 HTTP 错误 400“客户端发送的请求在语法上不正确”响应。直到我意识到上面没有默认构造函数，@RequestBody MyJsonValueObject所以反序列化它有问题。但是，这个问题以这种方式提出。
So if you are using POST and objects, and getting errors like this, make sure you have a default constructor! Add some JUnit to be sure you can deserialise that object.
因此，如果您正在使用 POST 和对象，并收到这样的错误，请确保您有一个默认构造函数！添加一些 JUnit 以确保您可以反序列化该对象。
Note: I'm not saying this is the only reason you get this error. The original case used just String (which does have a default constructor !) so it's a little different. But in both cases it appears the request URI appears to have been mapped to the right method, and something has gone wrong trying to extract parameters from the HTTP request.
注意：我并不是说这是您收到此错误的唯一原因。原始案例只使用 String （它确实有一个默认构造函数！）所以它有点不同。但在这两种情况下，请求 URI 似乎已映射到正确的方法，并且在尝试从 HTTP 请求中提取参数时出现问题。
回答by Anthony Nguyen
My problem was due to the incorrect mapping of the @RequestBody object.
我的问题是由于 @RequestBody 对象的映射不正确。
My Request Body looks like this
我的请求正文看起来像这样
{data: ["1","2","3"]}
I had the following code in my controller
我的控制器中有以下代码
@RequestMapping(value = "/mentee", method = RequestMethod.POST)
public @ResponseBody boolean updateData(@RequestBody List<Integer> objDTO, HttpSession session) {
...
}
This give me HTTP 400 because Spring doesn't know how to bind my Json data to a List.
这给了我 HTTP 400，因为 Spring 不知道如何将我的 Json 数据绑定到列表。
I changed the RequestBody object to the following
我将 RequestBody 对象更改为以下内容
@RequestMapping(value = "/mentee", method = RequestMethod.POST)
public @ResponseBody boolean updateData(@RequestBody ObjectiveDto objDTO, HttpSession session) {
...
}
and defined ObjectiveDto as followed
并定义 ObjectiveDto 如下
@ToString
public class ObjectiveDto {
@Getter @Setter
private List<Integer> data;
}
This resolved the HTTP 400 error.
这解决了 HTTP 400 错误。
