C++ Arduino 中的向量

Vectors in Arduino

提问by jakebird451

I am making a vector of "waypoints" on the Arduino. Each waypoint is an object. The Arduino will obviously need to store multiple waypoints for waypoint navigation. But instead of storing these waypoints in a standard preprogrammed array, the user will need to be able to add, remove waypoints and move them around. Unfortunately the Arduino does not offer a vector type as a built-in library.

我正在 Arduino 上制作“航点”向量。每个航点都是一个对象。Arduino 显然需要为航点导航存储多个航点。但是，不是将这些航路点存储在标准的预编程阵列中，用户需要能够添加、删除航路点并四处移动它们。不幸的是，Arduino 没有提供矢量类型作为内置库。

I am currently contemplating two options:

我目前正在考虑两种选择：

1. In Container for objects like C++ 'vector'?, someone posted a general purpose library. It does not contain any index deletion, or movement operations. But it does contain some memory management strategies.

2. I have used malloc, dealloc, callocin the past. But I do not like that option at all, especially with classes. But is this a better option in my senario?

1. 在C++ 'vector' 之类的对象的容器中？，有人发布了一个通用库。它不包含任何索引删除或移动操作。但它确实包含一些内存管理策略。

2. 我过去使用过malloc、 dealloc 、calloc。但我根本不喜欢那个选项，尤其是在课堂上。但在我的情景中，这是一个更好的选择吗？

Which one is a better path to go down?

哪一条是更好的下山之路？

回答by Sibster

Standard C++ for Arduinomight be an option. It lets you use the STLvectorin Arduino.

Arduino 的标准 C++可能是一种选择。它允许您在 Arduino 中使用STL向量。

回答by MrT

You can write this LinkedList template class and simply call it wherever you want :

你可以编写这个 LinkedList 模板类，然后在任何你想要的地方调用它：

#ifndef LinkedList_hpp
#define LinkedList_hpp


template <class T>
class ListNode {
  public:
    T element;
    ListNode* next;
    ListNode* prev;

    ListNode(T element, ListNode* prev, ListNode* next) : element(element)
    {
      this->next = next;
      this->prev = prev;
    };
};

template <class T>
class LinkedList  {
  private:
    int length;
    ListNode<T>* head;
    ListNode<T>* tail;
    ListNode<T>* curr;
  public:
    LinkedList();
    LinkedList(const LinkedList<T>&);
    ~LinkedList();
    T& getCurrent();
    T& First() const;
    T& Last() const;
    int getLength();
    void Append(T);
    void DeleteLast();
    void DeleteFirst();
    void DeleteCurrent();
    bool next();
    bool moveToStart();
    bool prev();
    void Delete(T&);
    bool Search(T);
    void Clear();
    void PutFirstToLast();
    void Update(T elem);
    LinkedList& operator = (const LinkedList<T>&);
};

template <class T>
LinkedList<T>::LinkedList() {
    length = 0;
    head = nullptr;
    tail = nullptr;
    curr = nullptr;
}

template <class T>
LinkedList<T>::LinkedList(const LinkedList<T> & list) {
    length = 0;
    head = nullptr;
    tail = nullptr;
    curr = nullptr;

    ListNode<T> * temp = list.head;

    while(temp != nullptr)
    {
        Append(temp->element);
        temp = temp->next;
    }
}

template <class T>
LinkedList<T> & LinkedList<T>::operator=(const LinkedList<T> & list)
{
    Clear();

    ListNode<T> * temp = list.head;

    while(temp != nullptr)
    {
        Append(temp->element);
        temp = temp->next;
    }

    return *this;
}

template <class T>
LinkedList<T>::~LinkedList() {
    Clear();
}

template<class T>
T& LinkedList<T>::getCurrent()
{
  return curr->element;
}

template<class T>
T& LinkedList<T>::First() const
{
  return head->element;
}

template<class T>
T& LinkedList<T>::Last() const
{
  return tail->element;
}

template<class T>
int LinkedList<T>::getLength()
{
  return length;
}

template <class T>
void LinkedList<T>::Append(T element)
{
    ListNode<T> * node = new ListNode<T>(element, tail, nullptr);

    if(length == 0)
        curr = tail = head = node;
    else {
        tail->next = node;
        tail = node;
    }

    length++;

}

template <class T>
void LinkedList<T>::DeleteLast()
{
    if(length == 0)
      return;
    curr = tail;
    DeleteCurrent();
}

template <class T>
void LinkedList<T>::DeleteFirst()
{
    if(length == 0)
      return;
    curr = head;
    DeleteCurrent();
}

template <class T>
bool LinkedList<T>::next()
{
    if(length == 0)
        return false;

    if(curr->next == nullptr)
        return false;

    curr = curr->next;
    return true;
}

template <class T>
bool LinkedList<T>::moveToStart()
{
    curr = head;
    return length != 0;
}

template<class T>
bool LinkedList<T>::prev()
{
    if(length == 0)
        return false;

    if(curr->prev != nullptr)
        return false;

    curr = curr->prev;
    return true;
}

template <class T>
void LinkedList<T>::Delete(T & elem)
{
    if(Search(elem))
        DeleteCurrent();
}

template <class T>
void LinkedList<T>::DeleteCurrent()
{
    if(length == 0)
        return;
    length--;
    ListNode<T> * temp = curr;

    if(temp->prev != nullptr)
        temp->prev->next = temp->next;
    if(temp->next != nullptr)
        temp->next->prev = temp->prev;

    if(length == 0)
        head = curr = tail = nullptr;
    else if(curr == head)
        curr = head = head->next;
    else if(curr == tail)
        curr = tail = tail->prev;
    else
        curr = curr->prev;

     delete temp;
}

template <class T>
bool LinkedList<T>::Search(T elem)
{
    if(length == 0)
        return false;
    if(moveToStart())
        do {
            if(curr->element == elem)
                return true;
        } while (next());
    return false;
}

template <class T>
void LinkedList<T>::PutFirstToLast()
{
  if(length < 2)
    return;
  ListNode<T>* temp = head->next;
  head->next->prev = nullptr;
  head->next = nullptr;
  head->prev = tail;
  tail->next = head;
  tail = head;
  head = temp;
}

template <class T>
void LinkedList<T>::Update(T elem)
{
    if(Search(elem))
        curr->element = elem;
}

template <class T>
void LinkedList<T>::Clear()
{
    if(length == 0)
        return;
    ListNode<T> * temp = head;

    while(temp != nullptr)
    {
        head = head->next;
        delete temp;
        temp = head;
    }

    head = curr = tail = nullptr;

    length = 0;

}


#endif

Use this class as follow:

使用这个类如下：

LinkedList<int> list;

list.Append(1);
list.Append(2);
list.Append(3);
list.Append(4);

int my_integer;

if(list.moveToStart())
    do{
        my_integer = list.getCurrent();
    }while(list.next());

回答by augustzf

Sounds like you would want to implement a simple linked list. A linked list allows you to move objects (waypoints, in your case) around without the overhead associated with C++ vectors.

听起来您想要实现一个简单的链表。链表允许您在没有与 C++ 向量相关的开销的情况下移动对象（在您的情况下为航点）。

Here's an implementation on GitHub.

这是GitHub 上的一个实现。

回答by Visual Micro

The arduino has limited memory so you need to know how many waypoints you will allow. In which case a simple array to hold memory pointers (addresses) of allocated waypoints will provide the sequence/order you need. Keeping one array slot free as a working area will allow waypoints to be moved around (re-ordered).

arduino 的内存有限，因此您需要知道您将允许多少个航路点。在这种情况下，一个简单的数组来保存分配的航点的内存指针（地址）将提供您需要的序列/顺序。保持一个阵列插槽空闲作为工作区域将允许移动航点（重新排序）。

回答by Jake

You could also have a fixed array of waypoint structures and include a variable in the structure if the waypoint is in use or not. When adding a waypoint, all you have to loop through the array until you find a structure that is not in use.

您还可以拥有一个固定的航点结构数组，并在该结构中包含一个变量（如果该航点正在使用或未使用）。添加航点时，您必须遍历数组，直到找到未使用的结构。