Python：类型错误：列表索引必须是整数，而不是 str
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Python: TypeError: list indices must be integers, not str
提问by Chalanthorn Chanmathikornkul
I'm going to do Matrix Addition on Python.(Not finish). But it shows an error.
我将在 Python 上进行矩阵加法。（未完成）。但它显示一个错误。
m, n = (int(i) for i in raw_input().split())
a = [[0 for i in range(m)] for j in range(n)]
b = [[0 for i in range(m)] for j in range(n)]
c = []
total = []
for i in range(m):
x = raw_input()
for j in range(n):
value = [int(i) for i in x.split()]
c[i][j] = a[i][j]
#c.append(value)
print a
for i in c:
print i
I want to input
我要输入
3 3 <-- matrix dimensional m*n
3 3 <-- 矩阵维数 m*n
1 2 3 >
1 2 3 >
3 2 1 > matrix A
3 2 1 > 矩阵 A
1 3 2 >
1 3 2 >
1 1 1 >
1 1 1 >
1 1 1 > matrix B
1 1 1 > 矩阵 B
1 1 1 >
1 1 1 >
and shows as
并显示为
2 3 4 >
2 3 4 >
4 3 2 > matrix A + B
4 3 2 > 矩阵 A + B
2 4 3 >
2 4 3 >
采纳答案by cdarke
You are using iin your outer forloop, and it is an int. Then in the loop you have:
您i在外for循环中使用，它是一个 int。然后在循环中你有：
value = [int(i) for i in x.split()]
which makes ia string (which is what splitreturns). Maybe you think there is some sort of scoping inside [ ]? There isn't. You have a name collision, change one of them.
它生成i一个字符串（这是split返回的内容）。也许你认为里面有某种范围界定[ ]？没有。您遇到了名称冲突，请更改其中之一。
回答by Nilesh
You are using same variable in inner for loop.
您在内部 for 循环中使用相同的变量。
for i in range(m):
x = raw_input()
for j in range(n):
# variable i is refering to outer loop
value = [int(p) for p in x.split()]
c[i][j] = a[i][j]
#c.append(value)
print a
for i in c:
print i
回答by cezar
Beyond the first two answers you'll have a problem with this statement:
除了前两个答案之外，您还会遇到以下语句的问题：
c[i][j] = a[i][j]
When the loop starts iwill be 0 and that's so far OK, but cis an empty list and has no iterable at the first position so c[0][0]will return an error.
Get rid of it and uncomment the following line:
循环开始时i将为 0，到目前为止还可以，但它c是一个空列表，并且在第一个位置没有可迭代对象，因此c[0][0]将返回错误。摆脱它并取消注释以下行：
#c.append(value)
EDIT:
编辑：
Your code won't return what you want. You'd better make something like this to create a matrix with the given sides:
您的代码不会返回您想要的内容。你最好做这样的事情来创建一个给定边的矩阵：
for i in range(m):
d = []
for j in range(n):
x = raw_input()
d.append(int(x))
c.append(d)
If you have 3 for both mand n, then you will create matrix with sides 3 x 3 saved in the variable c.
In this way you don't have to split the user input. The user can give a number at a time. And you could even change the following line:
如果您有 3m和3 n，那么您将创建边 3 x 3 保存在变量中的矩阵c。通过这种方式，您不必拆分用户输入。用户可以一次给出一个号码。您甚至可以更改以下行：
x = raw_input()
to:
到：
x = raw_input("{0}. row, {1}. column: ".format(i+1, j+1))
Try it out!
试试看！
回答by Chalanthorn Chanmathikornkul
import time
m, n = (int(i) for i in raw_input().split())
a = []
b = []
total = [[0 for i in range(n)] for j in range(m)]
for i in range(m):
x = raw_input()
for j in range(n):
value = [int(i) for i in x.split()]
a.append(value)
#print a
for i in range(m):
x = raw_input()
for j in range(n):
value = [int(i) for i in x.split()]
b.append(value)
#print b
for i in range(m):
for j in range(n):
total[i][j] = a[i][j] + b[i][j]
for i in total:
print ' '.join(map(str, i))
time.sleep(2)
OK! I just figured it out! Thank you
好的！我刚刚想通了！谢谢
回答by r_2
you can also hit this error if you declare an int and treat it like a dict
如果您声明一个 int 并将其视为一个 dict，您也可能遇到此错误
>>> a = []
>>> a['foo'] = 'bar'
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: list indices must be integers, not str
