java 性格比较
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Character Comparison
提问by Vernah
I'm currently doing an online course, however it doesn't seem to enjoy this method: Character.isWhiteSpace(c)
我目前正在做一个在线课程，但它似乎并不喜欢这种方法： Character.isWhiteSpace(c)
What other methods are there that can answer the below question?
还有哪些方法可以回答以下问题？
Assume that cis a char variable has been declared and already given a value. Write an expression whose value is true if and only if xis what is called a whitespace character (that is a space or a tab or a newline-- none of which result in ink being printed on paper).
假设c已经声明了一个 char 变量并且已经给定了一个值。编写一个表达式，其值为真当且仅当x是所谓的空白字符（即空格、制表符或换行符——它们都不会导致墨水打印在纸上）。
回答by Jon Newmuis
回答by Bohemian
There is a java API for this: Character.isWhiteSpace(c)
有一个Java API： Character.isWhiteSpace(c)
回答by ratchet freak
if you don't want to/can't use libraries
如果您不想/不能使用库
c==' '||c=='\t'||c=='\n'||c=='\r'
note that \ris a carriage return it's part of the windows \r\ncombination (and used commonly in network protocols)
请注意，这\r是一个回车，它是 windows\r\n组合的一部分（并且通常用于网络协议）
