php 如何使用php从数据库/文件夹下载文件
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How to download file from database/folder using php
提问by nazerol
File uploaded will be store in database and folder (folder name: uploads).Now I want to know how to create download file from database/folder. I have two file butangDonload.php and download.php. When user click word "donload" the pop up box will appear and save the file.
上传的文件将存储在数据库和文件夹中（文件夹名称：uploads）。现在我想知道如何从数据库/文件夹创建下载文件。我有两个文件butangDonload.php 和download.php。当用户单击单词“donload”时，将出现弹出框并保存文件。
butangDonload.php
butangDonload.php
<?php
$file = "Bang.png"; //Let say If I put the file name Bang.png
echo "<a href='download.php?nama=".$file."'>donload</a> ";
?>
download.php
下载.php
<?php
$name= $_GET['nama'];
download($name);
function download($name) {
$file = $nama_fail;
if (file_exists($file)) {
header('Content-Description: File Transfer');
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename='.basename($file));
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: must-revalidate');
header('Pragma: public');
header('Content-Length: ' . filesize($file));
ob_clean();
flush();
readfile($file);
exit;
}
}
?>
回答by Suman Immortal Maharzan
I have changed to your code with little modification will works well. Here is the code:
我已更改为您的代码，稍加修改即可正常工作。这是代码：
butangDonload.php
butangDonload.php
<?php
$file = "logo_ldg.png"; //Let say If I put the file name Bang.png
echo "<a href='download1.php?nama=".$file."'>download</a> ";
?>
download.php
下载.php
<?php
$name= $_GET['nama'];
header('Content-Description: File Transfer');
header('Content-Type: application/force-download');
header("Content-Disposition: attachment; filename=\"" . basename($name) . "\";");
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: must-revalidate');
header('Pragma: public');
header('Content-Length: ' . filesize($name));
ob_clean();
flush();
readfile("your_file_path/".$name); //showing the path to the server where the file is to be download
exit;
?>
Here you need to show the path from where the file to be download. i.e. will just give the file name but need to give the file path for reading that file. So, it should be replaced by I have tested by using your code and modifying also will works.
在这里，您需要显示要下载文件的路径。即只提供文件名，但需要提供读取该文件的文件路径。因此，它应该被替换为我已经使用您的代码进行了测试并且修改也将起作用。
回答by luke
here is the code to download file with how much % it is downloaded
这是下载文件的代码，下载了多少％
<?php
$ch = curl_init();
$downloadFile = fopen( 'file name here', 'w' );
curl_setopt($ch, CURLOPT_URL, "file link here");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_BUFFERSIZE, 65536);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_PROGRESSFUNCTION, 'downloadProgress');
curl_setopt($ch, CURLOPT_NOPROGRESS, false);
curl_setopt( $ch, CURLOPT_FILE, $downloadFile );
curl_exec($ch);
curl_close($ch);
function downloadProgress ($resource, $download_size, $downloaded_size, $upload_size, $uploaded_size) {
if($download_size!=0){
$percen= (($downloaded_size/$download_size)*100);
echo $percen."<br>";
}
}
?>
回答by Dhaval Rathod
You can use html5 tag to download the image directly
可以使用html5标签直接下载图片
<?php
$file = "Bang.png"; //Let say If I put the file name Bang.png
echo "<a href='download.php?nama=".$file."' download>donload</a> ";
?>
For more information, check this link http://www.w3schools.com/tags/att_a_download.asp
有关更多信息，请查看此链接 http://www.w3schools.com/tags/att_a_download.asp
回答by bala 3057258
butangDonload.php
$file = "Bang.png"; //Let say If I put the file name Bang.png
$_SESSION['name']=$file;
Try this,
尝试这个，
<?php
$name=$_SESSION['name'];
download($name);
function download($name){
$file = $nama_fail;
?>
回答by Suman Immortal Maharzan
You can also use the following code:
<?php
$filename = $_GET["nama"];
$contenttype = "application/force-download";
header("Content-Type: " . $contenttype);
header("Content-Disposition: attachment; filename=\"" . basename($filename) . "\";");
readfile("your file uploaded path".$filename);
exit();
?>
