Javascript 匹配正则表达式中的特殊字符和字母
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Matching special characters and letters in regex
提问by Khaleel
I am trying to validate a string, that should contain letters numbers and special characters &-._only. For that I tried with a regular expression.
我正在尝试验证一个字符串，该字符串应仅包含字母数字和特殊字符&-._。为此，我尝试使用正则表达式。
var pattern = /[a-zA-Z0-9&_\.-]/
var qry = 'abc&*';
if(qry.match(pattern)) {
alert('valid');
}
else{
alert('invalid');
}
While using the above code, the string abc&*is valid. But my requirement is to show this invalid. ie Whenever a character other than a letter, a number or special characters &-._comes, the string should evaluate as invalid. How can I do that with a regex?
使用上述代码时，字符串abc&*有效。但我的要求是证明这个无效。即，每当出现字母、数字或特殊字符以外的字符时&-._，该字符串应评估为无效。我怎么能用正则表达式做到这一点？
回答by Highly Irregular
Add them to the allowed characters, but you'll need to escape some of them, such as -]/\
将它们添加到允许的字符中，但您需要对其中的一些字符进行转义，例如 -]/\
var pattern = /^[a-zA-Z0-9!@#$%^&*()_+\-=\[\]{};':"\|,.<>\/?]*$/
That way you can remove any individual character you want to disallow.
这样您就可以删除您想要禁止的任何单个字符。
Also, you want to include the start and end of string placemarkers ^ and $
此外，您希望包含字符串地标 ^ 和 $ 的开始和结束
Update:
更新：
As elclanrs understood (and the rest of us didn't, initially), the onlyspecial characters needing to be allowed in the pattern are &-._
正如 elclanrs 所理解的（我们其他人最初没有理解），模式中唯一需要允许的特殊字符是 &-._
/^[\w&.\-]+$/
[\w] is the same as [a-zA-Z0-9_]
[\w] 与 [a-zA-Z0-9_] 相同
Though the dash doesn't need escaping when it's at the start or end of the list, I prefer to do it in case other characters are added. Additionally, the + means you need at least one of the listed characters. If zero is ok (ie an empty value), then replace it with a * instead:
虽然破折号在列表的开头或结尾不需要转义，但我更喜欢在添加其他字符的情况下这样做。此外，+ 表示您至少需要列出的字符之一。如果零没问题（即空值），则将其替换为 *：
/^[\w&.\-]*$/
回答by Ja?ck
Well, why not just add them to your existing character class?
那么，为什么不将它们添加到您现有的字符类中呢？
var pattern = /[a-zA-Z0-9&._-]/
If you need to check whether a string consists of nothing but those characters you have to anchorthe expression as well:
如果您需要检查字符串是否只包含这些字符，您还必须锚定表达式：
var pattern = /^[a-zA-Z0-9&._-]+$/
The added ^and $match the beginning and end of the string respectively.
添加的^和$匹配的分别是字符串的开头和结尾。
Testing for letters, numbers or underscore can be done with \wwhich shortens your expression:
可以测试字母、数字或下划线，\w以缩短您的表达式：
var pattern = /^[\w&.-]+$/
As mentioned in the comment from Nathan, if you're not using the results from .match()(it returns an array with what has been matched), it's better to use RegExp.test()which returns a simple boolean:
正如 Nathan 的评论中所提到的，如果您不使用结果.match()（它返回一个包含匹配内容的数组），最好使用RegExp.test()which 返回一个简单的布尔值：
if (pattern.test(qry)) {
// qry is non-empty and only contains letters, numbers or special characters.
}
Update 2
更新 2
In case I have misread the question, the below will check if all three separate conditions are met.
如果我误读了这个问题，下面将检查是否满足所有三个单独的条件。
if (/[a-zA-Z]/.test(qry) && /[0-9]/.test(qry) && /[&._-]/.test(qry)) {
// qry contains at least one letter, one number and one special character
}
回答by elclanrs
Try this regex:
试试这个正则表达式：
/^[\w&.-]+$/
Also you can use test.
你也可以使用test.
if ( pattern.test( qry ) ) {
// valid
}
回答by Amrutha VS
let pattern = /^(?=.*[0-9])(?=.*[!@#$%^&*])(?=.*[a-z])(?=.*[A-Z])[a-zA-Z0-9!@#$%^&*]{6,16}$/;
//following will give you the result as true(if the password contains Capital, small letter, number and special character) or false based on the string format
let reee =pattern .test("helLo123@"); //true as it contains all the above
回答by chadalavada harish
Try this RegEx: Matching special charecters which we use in paragraphs and alphabets
试试这个正则表达式：匹配我们在段落和字母表中使用的特殊字符
Javascript : /^[a-zA-Z]+(([\'\,\.\-_ \/)(:][a-zA-Z_ ])?[a-zA-Z_ .]*)*$/.test(str)
.test(str) returns boolean value if matched true and not matched false
c# : ^[a-zA-Z]+(([\'\,\.\-_ \/)(:][a-zA-Z_ ])?[a-zA-Z_ .]*)*$
