javascript 如何将 2 个字母的特定组合与正则表达式匹配
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how to match specific combination of 2 letters with regex
提问by PhilMr
given this set of letters
鉴于这组字母
xx | af | an | bf | bn | cf | cn
xx | 阿夫| 一个 | 男朋友 | 十亿 | 比照 | cn
how can I see if, given two characters, they match against one of the above?
给定两个字符，我如何查看它们是否与上述字符之一匹配？
I could easily hardcode the solution with a switch case, but I think regex is a more elegant solution.
我可以使用 switch case 轻松地对解决方案进行硬编码，但我认为 regex 是一个更优雅的解决方案。
回答by Brian Stephens
You basically wrote the regex yourself:
您基本上自己编写了正则表达式：
xx|af|an|bf|bn|cf|cn
xx|af|an|bf|bn|cf|cn
回答by hwnd
You wrote the regular expression yourself as stated previously, you could simplify it to...
如前所述，您自己编写了正则表达式，您可以将其简化为...
var re = /xx|[abc][fn]/
回答by CMPS
回答by Federico Piazza
You can use this code:
您可以使用此代码：
// regex to match your words
var re = /\b(xx|af|an|bf|bn|cf|cn)\b/g;
// your text string
var str = 'as ww zx af ad we re an ana ';
var m;
while ((m = re.exec(str)) != null) {
if (m.index === re.lastIndex) {
re.lastIndex++;
}
// View your result using the m-variable.
// eg m[0] etc.
}
