C语言 C (Arduino) 中的字符串数组（字符数组）。我该如何实现？
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Array of strings (char array) in C (Arduino). How do I accomplish it?
提问by z3cko
I want to access certain data which basically looks like this:
我想访问某些基本如下所示的数据：
char* a[]={
"0000000000",
"0000000000",
"0011111100",
"0000100100",
"0000100100",
"0011111100",
"0000000000",
"0000000000",
};
I have around 200 of those data sets and want to access it in the way.
我有大约 200 个这样的数据集，并希望以这种方式访问它。
fooBar[23];--> This should return the 23rd character array (which looks like the example listed above).
fooBar[23];--> 这应该返回第 23 个字符数组（看起来像上面列出的例子）。
As far as I understand from my other programming knowledge, I would need an array of Strings. The array index is my lookup number (which will be a maximum of 255). The array values are the character arrays as shown above.
据我了解其他编程知识，我需要一个字符串数组。数组索引是我的查找编号（最多为 255）。数组值是如上所示的字符数组。
How can this be accomplished with C (Arduino IDE)?
如何使用 C (Arduino IDE) 实现这一点？
回答by taufique
Just use a two dimensional array. Like:
只需使用二维数组。喜欢：
char a[][]={
"0000000000",
"0000000000",
"0011111100",
"0000100100",
"0000100100",
"0011111100",
"0000000000",
"0000000000",
};
回答by hmjd
Based on your comment, I thinkthis is what you are asking for:
根据您的评论，我认为这就是您的要求：
const char* data_sets[][200] =
{
{ "00000", "11111", },
{ "22222", "33333", "44444" },
{ "55555" },
};
Each entry in data_setsis an array of 200 const char*. For accessing:
中的每个条目data_sets都是一个 200 的数组const char*。访问：
for (size_t i = 0; i < sizeof(data_sets) / sizeof(data_sets[0]); i++)
{
const char** data_set = data_sets[i];
printf("data_set[%u]\n", i);
for (size_t j = 0; data_set[j]; j++)
{
printf(" [%s]\n", data_set[j]);
}
}
See online demo at http://ideone.com/6kq2M.
请参阅http://ideone.com/6kq2M 上的在线演示。
