Javascript 如何检查数组中是否存在jQuery对象？
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How to check if jQuery object exist in array?
提问by Misha Moroshko
Given an itemand an array, I would like to know if itemexist in array.
给定一个item和array，我想知道是否item存在array。
itemis a jQuery object, e.g. $(".c"). You can assume that item.length == 1.
item是一个 jQuery 对象，例如$(".c"). 你可以假设item.length == 1。
arrayis an array of jQuery objects, e.g. [$(".a"), $(".b")]. Each item in this array may represent 0, 1, or more objects.
array是一个 jQuery 对象数组，例如[$(".a"), $(".b")]. 这个数组中的每一项都可以代表 0、1 或更多的对象。
Here is how I thought to implement this: (live demo here)
这是我想如何实现这个：（现场演示在这里）
function inArray(item, arr) {
for (var i = 0; i < arr.length; i++) {
var items = $.makeArray(arr[i]);
for (var k = 0; k < items.length; k++) {
if (items[k] == item[0]) {
return true;
}
}
}
return false;
}
Can you find a more elegant implementation?
你能找到更优雅的实现吗？
Example:
例子：
HTML:
HTML：
<div class="a">Hello</div>
<div class="a">Stack</div>
<div class="a">Overflow</div>
<div class="b">Have</div>
<div class="b">a</div>
<div class="b">nice</div>
<div class="b">day!</div>
<div class="c">Bye bye</div>
JS:
JS：
console.log(inArray($(".a").eq(2), [$(".a"), $(".b")])); // true
console.log(inArray($(".b").eq(3), [$(".a"), $(".b")])); // true
console.log(inArray($(".c"), [$(".a"), $(".b")])); // false
console.log(inArray($(".a").eq(2), [$(".b")])); // false
console.log(inArray($(".a").eq(2), [])); // false
console.log(inArray($(".c"), [$("div")])); // true
回答by Misha Moroshko
According to Felix's suggestion:
根据菲利克斯的建议：
[$(selector1), $(selector2), ... ]can be simplified to
[$(selector1), $(selector2), ... ]可以简化为
$(selector1, selector2, ...)
or
或者
$(selector1).add(selector2)...
and then it can be implemented as:
然后它可以实现为：
function inArray(item, arr) {
return (arr.index(item) != -1);
}
回答by Snake Eyes
what about
关于什么
if(jQuery.inArray(some, array) === -1)
{
//process data if "some" is not in array
}
else
{
//process if "some" is in array
}
read here : http://api.jquery.com/jQuery.inArray/
回答by Umesh Patil
if($.inArray("valueYouWantToFind", nameOfTheArray) == true) {
Your code;
}
Eg.,
var userChoice = ["yes"];
if($.inArray('yes',userChoice) == true) {
alert("found");
}
回答by Kirill Popov
console.log(!!~$.inArray("a", ["a", "b", "c"]));
回答by Manjur Gani
data = [
{val:'xxx',txt:'yyy'},
{val:'yyy',txt:'aaa'},
{val:'bbb',txt:'ccc'}
];
var dummyArray = [];
var distinctValueArray = [];
$.each(data, function (index, firstobject) {
//push first element of object in both dummy array and distinct array.
if (index == 0) {
distinctValueArray.push(firstobject);
dummyArray.push(firstobject.txt);
}
else {
//started from 2nd index.
if ($.inArray(firstobject.txt, dummyArray) == -1) {
distinctValueArray.push(firstobject);
}
dummyArray.push(firstobject.txt);
}
});
dummyArray.length=0;
