Java 使用 BigInteger 乘法运算符
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Using BigInteger Multiply operator
提问by Steffan Harris
I was wondering if there was a way to multiply BigIntegervariables together, because the *operator cannot be applied to BigInteger.
我想知道是否有办法将BigInteger变量相乘，因为*运算符不能应用于BigInteger.
So I was wondering if it was possible to multiply two BigIntegerstogether without using the *operator.
所以我想知道是否可以在BigIntegers不使用*运算符的情况下将两个相乘。
采纳答案by jjnguy
You use BigIntegersmultiply()method like so:
您可以像这样使用BigIntegersmultiply()方法：
BigInteger int1 = new BigInteger("131224324234234234234313");
BigInteger int2 = new BigInteger("13345663456346435648234313");
BigInteger result = int1.multiply(int2)
I should have pointed out a while ago that BigIntegeris immutable. So any result of an operation has to be stored into a variable. The operator or operand are never changed.
我应该在不久前指出这BigInteger是不可变的。因此，操作的任何结果都必须存储到变量中。运算符或操作数永远不会改变。
回答by swilliams
You can use the multiply(BigInteger) method in BigInteger. So:
您可以在 BigInteger 中使用 multiply(BigInteger) 方法。所以：
BigInteger result = someBigInt.multiply(anotherBigInt);
回答by waweru
Easier way to implement:
更简单的实现方式：
int i = 5;
BigInteger bigInt = new BigInteger("12345678901");
BigInteger result = bigInt.multiply(BigInteger.valueOf(i))
回答by wolfran
The result multiplying these specific factors
乘以这些特定因素的结果
A: 131224324234234234234313
答：131224324234234234234313
B: 13345663456346435648234313
乙：13345663456346435648234313
Could be this one (I hope I am correct):
可能是这个（我希望我是正确的）：
R: 1751275668516575787795211751170772134115968581969
回复：1751275668516575787795211751170772134115968581969
Both are considered being two positive integers. And the technique used was Karatsuba's method
两者都被认为是两个正整数。使用的技术是唐叶的方法
int ab = (mul1) * 10^n + (mul3 - mul1 - mul2) * 10^n/2 + mul2;
int ab = (mul1) * 10^n + (mul3 - mul1 - mul2) * 10^n/2 + mul2;
