PHP 中的 For 循环表
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For Loop Table in PHP
提问by Afnizar Nur Ghifari
I am trying to generate a table with php for loop, that lists numbers. Something like this:
我正在尝试使用 php for 循环生成一个表，其中列出了数字。像这样的东西：
1 | 2 | 3 | 4 | 5
2 | 3 | 4 | 5 | 1
3 | 4 | 5 | 1 | 2
4 | 5 | 1 | 2 | 3
5 | 1 | 2 | 3 | 4
I still have problems getting it, this is actually quite simple, but I have not been able to solve it. So far I have the following code:
我还是有问题，这其实很简单，但我一直没能解决。到目前为止，我有以下代码：
<?php
echo "<table border='1'><br />";
for ($row = 0; $row < 5; $row ++) {
echo "<tr>";
for ($col = 1; $col <= 4; $col ++) {
echo "<td>", ($col + ($row * 4)), "</td>";
}
echo "</tr>";
}
echo "</table>";
?>
However, this only generates the following:
但是，这只会生成以下内容：
1 | 2 | 3 | 4
5 | 6 | 7 | 8
9 | 10 | 11 | 12
13 | 14 | 15 | 16
17 | 18 | 19 | 20
Thank you, any help would be appreciated!
谢谢，任何帮助将不胜感激！
回答by remudada
<?php
echo "<table border='1'><br />";
for ($row = 0; $row < 5; $row ++) {
echo "<tr>";
for ($col = 0; $col < 5; $col ++) {
echo "<td>", (($col + $row) % 5) + 1, "</td>";
}
echo "</tr>";
}
echo "</table>";
?>
回答by blue
echo "<table border='1'><br />";
for ( $i = 0; $i < 5; $i++ ) {
echo "<tr>";
for ( $j = 0; $j < 5; $j++ ) {
echo "<td>", ($j+$i)%5+1, "</td>";
}
echo "</tr>";
}
echo "</table>";
回答by Hackerman
My version :
我的版本：
<?php
echo "<table border='1'><br />";
$i=1;
for ($row = 0; $row < 5; $row ++) {
echo "<tr>";
$cont = 0;
for ($col = $i; $col <= 5; $col ++)
{
echo "<td>", ($col), "</td>";
$cont++;
}
if($cont < 5)
{
for($col = 1; $col <= 5 - $cont; $col++)
{
echo "<td>", ($col), "</td>";
}
}
echo "</tr>";
$i++;
}
echo "</table>";
Codepad: http://codepad.viper-7.com/JZogNY
回答by Ali Nouman
My Version
我的版本
<?php
echo "<table border='1'><br />";
for ($row = 0; $row < 5; $row ++) {
$k=$row;
for ($col = 0; $col < 5; $col ++) {
echo "<td>", (($k++)%5)+1, "</td>";
}
echo "</tr>";
}
echo "</table>";
?>
回答by Ruiz24
<?php
echo '<table border="1">';
$i = 0;
for($i =1; $i<=5; $i++){
echo '<tr>
<td>'.$i.'</td>';
$x = 0;
for($x=1; $x<=4; $x++){
$y = $x + $i;
$z = ($y>5) ? $y-5 : $y;
echo '<td>'.$z.'</td>';
}
echo '</tr>';
}
echo '</table>';
?>
