如何让 cx-oracle 将查询结果绑定到字典而不是元组?

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时间:2020-09-18 22:13:29  来源:igfitidea点击:

How can I make cx-oracle bind the results of a query to a dictionary rather than a tuple?

pythonsqldatabaseoraclecx-oracle

提问by Peter

Here is my code. I would like to find a way to have results from a query returned as a list of dictionaries rather than list of tuples. It seems like cx_oracle supports this with parts of the documentation talking about 'binding'. Though I can't figure out how it works.

这是我的代码。我想找到一种方法将查询结果作为字典列表而不是元组列表返回。似乎 cx_oracle 支持这一点,文档的部分内容讨论了“绑定”。虽然我无法弄清楚它是如何工作的。

def connect():  
    dsn = cx_Oracle.makedsn("host", 1521, "sid")
    orcl = cx_Oracle.connect('scott/tiger@' + dsn)
    curs = orcl.cursor()
    sql = "select * from sometable"
    curs.execute(sql)
    result = curs.fetchall()
    for row in result:
        print row[13] #CATEGORY field order
        print row['CATEGORY'] # <- I want this to work ('CATEGORY' is the name of a field in the 'sometable' table)
    curs.close()

回答by rapdum

Bindvars are used to execute query such as

Bindvars 用于执行查询,例如

  • By name(given named parameters)

    cursor = self.db.cursor()
    cursor.execute("SELECT bookName, author from books where Id=:bookId" , bookId="155881")
    print cursor.bindnames()
    
  • 按名称(给定命名参数)

    cursor = self.db.cursor()
    cursor.execute("SELECT bookName, author from books where Id=:bookId" , bookId="155881")
    print cursor.bindnames()
    

will print : ['BOOKID']

将打印:['BOOKID']

  • by position given a list of values

    cursor = self.db.cursor()
    cursor.prepare("insert into books (bookId,title,author,price) values(:1, :2, :3, :4)")
    cursor.executemany(None, listOfbookwhichAreTuppleOf4Field )
    
  • 按位置给出值列表

    cursor = self.db.cursor()
    cursor.prepare("insert into books (bookId,title,author,price) values(:1, :2, :3, :4)")
    cursor.executemany(None, listOfbookwhichAreTuppleOf4Field )
    

To get what you expected you could try something like that:

为了得到你所期望的,你可以尝试这样的事情:

def connect():  
    dsn = cx_Oracle.makedsn("host", 1521, "sid")
    orcl = cx_Oracle.connect('scott/tiger@' + dsn)
    curs = orcl.cursor()
    sql = "select * from sometable"
    curs.execute(sql)
    desc = [d[0] for d in curs.description]
    result = [dict(zip(desc,line)) for line in curs]
    curs.close()

回答by Peter

Here is a quick and dirty. Feel post a better way.

这是一个又快又脏的。感觉发布更好的方法。

def connect():  
    dsn = cx_Oracle.makedsn("host", 1521, "sid")
    orcl = cx_Oracle.connect('scott/tiger@' + dsn)
    curs = orcl.cursor()
    sql = "select * from sometable"
    curs.execute(sql)
    fieldNumber = 0
    fieldNames={}
    for desc in curs.description:
        fieldNames[desc[0]]=fieldNumber
        fieldNumber+=1
    result = curs.fetchall()
    for row in result:
        print str(row[fieldNames['CATEGORY']])
    curs.close()