javascript 删除javascript字符串前后的多余空格
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Remove Extra Spaces Before and After javascript string
提问by user3135730
var $one = $('#oneClueShow');
var x = $("#clueOneInput").find('input[type=text]').val();
if(x == 'D R' || x == 'd r'|| x == 'D r'|| x == 'd R'|| x == 'd'|| x == 'r' || x == 'd R' || x == 'T A')
Above is a snippet of java/ I have. What it does is takes an input -- then checks for a match. The bug I'm looking to resolve is if there are spaces after or before it isn't recognized.
以上是我拥有的 java/ 片段。它所做的是接受一个输入——然后检查匹配。我要解决的错误是如果在无法识别前后有空格。
For example within the input someone can type 'D R' no problem. If a space is added like so 'D R ' then it no longer recognizes the input.
例如，在输入中，有人可以输入“DR”没问题。如果像这样添加空格 'DR ' 那么它就不再识别输入。
Is there something I can do to affect the input to ensure no space before/after prior to button click? I've been looking into replace, but can't seem to get it going.
我可以做些什么来影响输入以确保在单击按钮之前/之后没有空格？我一直在寻找更换，但似乎无法让它继续。
A reference for what I've been looking at : http://www.w3schools.com/jsref/jsref_replace.asp
我一直在看的参考资料：http: //www.w3schools.com/jsref/jsref_replace.asp
回答by ?????
回答by Gopinath Koothaperumal
回答by Gaurang Tandon
You can do a check before-hand:
您可以事先进行检查：
if (!String.prototype.trim) {
String.prototype.trim = function () {
return this.toString().replace(/^\s+|\s+$/g, '');
};
}
Will enable .trimin non-supported browsers. And then, you can use it like:
将.trim在不受支持的浏览器中启用。然后，您可以像这样使用它：
var x = $("#clueOneInput").find('input[type=text]').val().trim();
With the benefit that you can use this .trimmethod at many other places in the code too.
好处是您也可以.trim在代码的许多其他地方使用此方法。
回答by Amit Joki
Do this for cross-browser:
为跨浏览器执行此操作：
var x = $("#clueOneInput").find('input[type=text]').val().replace(/^\s+|\s+$/g,"");
回答by Naveen Chandra Tiwari
You should always use $.trim() while comparing the string. You can use $.trim() like:
在比较字符串时，您应该始终使用 $.trim()。您可以使用 $.trim() 像：
if($.trim(x) == 'D R' || $.trim(x) == 'd r'|| $.trim(x) == 'D r'|| $.trim(x) == 'd R'|| $.trim(x) == 'd'|| $.trim(x) == 'r' || $.trim(x) == 'd R' || $.trim(x) == 'T A')
