增加一个十六进制值 (JAVA)
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Increment a Hex value (JAVA)
提问by
can you increment a hex value in Java? i.e. "hex value" = "hex value"++
你能在 Java 中增加一个十六进制值吗？即“十六进制值”=“十六进制值”++
回答by Joachim Sauer
What do you mean with "hex value"? In what data type is your value stored?
“十六进制值”是什么意思？您的值存储在哪种数据类型中？
Note that int/short/char/... don't care how your value is represented initially:
请注意， int/short/char/... 不关心您的值最初是如何表示的：
int i1 = 0x10;
int i2 = 16;
i1and i2will have the exact same content. Java (and most other languages as well) don't care about the notation of your constants/values.
i1并且i2将有完全相同的内容。Java（以及大多数其他语言）不关心常量/值的表示法。
回答by Michael Myers
Yes. All ints are binary anyway, so it doesn't matter how you declare them.
是的。无论如何，所有整数都是二进制的，因此您如何声明它们并不重要。
int hex = 0xff;
hex++; // hex is now 0x100, or 256
int hex2 = 255;
hex2++; // hex2 is now 256, or 0x100
回答by Philip Reynolds
It depends how the hex value is stored. If you've got the hex value in a string, convert it to an Integer, increment and convert it back.
这取决于十六进制值的存储方式。如果您在字符串中有十六进制值，请将其转换为整数，递增并将其转换回来。
int value = Integer.parseInt(hex, 16);
value++;
String incHex = Integer.toHexString(value);
回答by Martin Cowie
Short answer: yes. It's
简短的回答：是的。它是
myHexValue++;
Longer answer: It's likely your 'hex value' is stored as an integer. The business of converting it into a hexadecimal (as opposed to the usual decimal) string is done with
更长的答案：很可能您的“十六进制值”存储为整数。将其转换为十六进制（而不是通常的十进制）字符串的业务是用
Integer.toHexString( myHexValue )
and from a hex string with
并从一个十六进制字符串
Integer.parseInt( someHexString, 16 );
M.
M。
回答by Steve Kuo
The base of the number is purely a UI issue. Internally an integer is stored as binary. Only when you convert it to human representation do you choose a numeric base. So you're question really boils down to "how to increment an integer?".
数字的基数纯粹是 UI 问题。在内部，整数存储为二进制。只有当您将其转换为人类表示时，您才能选择数字基础。所以你的问题真的归结为“如何增加一个整数？”。
