Java 如何找到数组中的奇数和偶数？
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How to find the Odd and Even numbers in an Array?
提问by Jeriel Ng
Right now, I'm trying to find the odd and even numbers of an array. Here's the code of what I have so far. I know my findEvens() and findOdds() methods are messed up because they keep giving me off values whenever I try to print the final result. For example, if I try to find the odds of {1,5,8,3,10}, it gives me {5,3,0}. And if I try to find the evens of {2,5,8,7,19}, it gives me {2,8,0}. Anyone know why?
现在，我正在尝试查找数组的奇数和偶数。这是我到目前为止所拥有的代码。我知道我的 findEvens() 和 findOdds() 方法搞砸了，因为每当我尝试打印最终结果时，它们都会给我提供值。例如，如果我试图找出 {1,5,8,3,10} 的几率，它会给出 {5,3,0}。如果我试图找到 {2,5,8,7,19} 的偶数，它会给我 {2,8,0}。有谁知道为什么？
public class Scores {
private int[] numbers;
public Scores(int[] numbersIn) {
numbers = numbersIn;
}
public int[] findEvens() {
int numberEvens = 0;
for (int i = 0; i < numbers.length; i++) {
if (i % 2 == 0) {
numberEvens++;
}
}
int[] evens = new int[numberEvens];
int count = 0;
for (int i = 0; i < numbers.length; i++) {
if (numbers[i] % 2 == 0) {
evens[count] = numbers[i];
count++;
}
}
return evens;
}
public int[] findOdds() {
int numberOdds = 0;
for (int i = 0; i < numbers.length; i++) {
if (i % 2 == 0) {
numberOdds++;
}
}
int[] odds = new int[numberOdds];
int count = 0;
for (int i = 1; i < numbers.length; i++) {
if (numbers[i] % 2 == 1) {
odds[count] = numbers[i];
count++;
}
}
return odds;
}
public double calculateAverage() {
int sum = 0;
for (int i = 0; i < numbers.length; i++) {
sum += numbers[i];
}
return (double) sum / numbers.length;
}
public String toString() {
String result = "";
for (int i = 0; i < numbers.length; i++) {
result += numbers[i] + "\t";
}
return result;
}
public String toStringInReverse() {
String result = "";
for (int i = numbers.length - 1; i >= 0; i--) {
result += numbers[i] + "\t";
}
return result;
}
}
采纳答案by drees
You're problem is in counting how many even numbers you have
你的问题是计算你有多少偶数
public int[] findEvens() {
int numberEvens = 0;
for (int i = 0; i < numbers.length; i++) {
if (i % 2 == 0) {
numberEvens++;
}
}
this will always return a number that is half the size of the length of numbers because you're doing mod division on the number of elements in the array, not on the elements themselves. Add numbers[i]to the ifstatement
这将始终返回一个数字长度的一半大小的数字，因为您正在对数组中的元素数量进行 mod 除法，而不是对元素本身进行除法。添加numbers[i]到if声明中
public int[] findEvens() {
int numberEvens = 0;
for (int i = 0; i < numbers.length; i++) {
if (numbers[i] % 2 == 0) {
numberEvens++;
}
}
looks like you've got the same problem with odd count
看起来你对奇数有同样的问题
回答by Omar Faroque Anik
'i' is used as conditional variable for looping. You should not divide this by 2. You have to divide the array element. like
'i' 用作循环的条件变量。您不应将其除以 2。您必须将数组元素除以。喜欢
if (numbers[i] % 2 == 0) {
numberEvens++;
}
then it should work. Thanks
那么它应该工作。谢谢
回答by Gaurav Sachdeva
Try This Code
试试这个代码
import java.util.Scanner;
public class OddEven {
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
System.out.println("enter number Elements in Array");
int n = s.nextInt();
int arr[] = new int[n];
System.out.println("enter Elements ");
for(int i=0; i<n; i++) {
arr[i]=s.nextInt();
}
int [] odd = filterOdd(arr);
try {
for(int i=0; i<n; i++) {
System.out.println("Odd" + odd[i]);
}
} catch(ArrayIndexOutOfBoundsException e) {}
int [] even = filterEven(arr);
try {
for(int i=0; i<n; i++) {
System.out.println("Even" + even[i]);
}
} catch(ArrayIndexOutOfBoundsException e) {}
}
public static int[] filterOdd(int[] a) {
int l = 0;
int j = 0;
for(int i=0; i<a.length; i++) {
if(a[i]%2==1) {
l++;
}
}
int k[]=new int[l];
for(int i=0; i<a.length; i++) {
if(a[i]%2==1) {
k[j] = a[i];
j++;
}
}
return k;
}
public static int[] filterEven(int[] a) {
int l = 0;
int j = 0;
for(int i=0; i<a.length; i++) {
if(a[i]%2==0) {
l++;
}
}
int k[] = new int[l];
for(int i=0; i<a.length; i++) {
if(a[i]%2==0) {
k[j] = a[i];
j++;
}
}
return k;
}
}
回答by Sabuj Karmaker
public class Array {
public static void main(String[] args) {
// TODO code application logic here
//Array declaration and value asign
int number[]=new int[]{1,2,3,4,5,6,7,8,9};
// for loop to move number
for(int p=0;p<number.length;p++)
{
// check number is even or odd??
if(number[p]%2==0)
System.out.println(number[p]+ " is Even number");
else
System.out.println( number[p]+" is odd umber");
}
}
}
回答by sunil waghole
Odd array one columns and another columns even array
奇数数组一列和另一列偶数数组
public class OddEven {
public static void main(String[] args) {
int arr[]={1,2,3,4,5,6,7,8};
int ss[]=new int[10];
int odd[]=new int[10];
int i;
int k;
for( i=0;i<arr.length;i++)
{
if(arr[i]%2==0)
{
ss[i]=arr[i];
System.out.print(""+ss[i]);
System.out.print(" ");
}
if((arr[i]%2)!=0)
{
odd[i]=arr[i];
System.out.print(""+odd[i]);
System.out.print(" ");
}else
{
System.out.println(" ");
}
}
}
}
========================================output==============================
1 2
3 4
5 6
7 8
========================================输出========== ====================== 1 2
3 4
5 6
7 8
