bash awk 和 md5:替换一列
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awk and md5: replace a column
提问by Florin Ghita
Starting from Awk replace a column with its hash value, I tried to hash(md5) a list of numbers:
从Awk开始用它的哈希值替换一列,我试图对一个数字列表进行哈希(md5):
$ cat -n file
1 40755462755
2 40751685373
3 40730094339
4 40722740446
5 40722740446
6 40743802204
7 40730094339
8 40745188886
9 40740593352
10 40745561530
If I run:
如果我运行:
cat file | awk '{cmd="echo -n " " | md5sum|cut -d\" \" -f1"; cmd|getline md5; =md5;print;}' | cat -n
1 29ece26ce4633b6e9480255db194cc40
2 120148eca0891d0fc645413d0f26b66b
3 cafc48d392a004f75b669f9d1d7bf894
4 7b4367e8f58835c0827dd6a2f61b7258
5 7b4367e8f58835c0827dd6a2f61b7258
6 49b12d1f3305ab93b33b330e8b1d3165
7 49b12d1f3305ab93b33b330e8b1d3165
8 bee44c89ac9d4e8e4e1f1c5c63088c71
9 f07262ac8f53755232c5abbf062364d0
10 2ac7c22170c00a3527eb99a2bfde2c2c
I don't know why the line 7 get the same md5 as line 6 because if I run them separately they are different:
我不知道为什么第 7 行与第 6 行得到相同的 md5,因为如果我单独运行它们,它们是不同的:
$ echo -n 40743802204 | md5sum|cut -d" " -f1
49b12d1f3305ab93b33b330e8b1d3165
$ echo -n 40730094339 | md5sum|cut -d" " -f1
cafc48d392a004f75b669f9d1d7bf894
I tried some prints:
我尝试了一些打印:
cat file| awk '{print while read -r num; do
echo -n $num | md5sum | cut -d ' ' -f1;
done < file
29ece26ce4633b6e9480255db194cc40
120148eca0891d0fc645413d0f26b66b
cafc48d392a004f75b669f9d1d7bf894
7b4367e8f58835c0827dd6a2f61b7258
7b4367e8f58835c0827dd6a2f61b7258
49b12d1f3305ab93b33b330e8b1d3165
cafc48d392a004f75b669f9d1d7bf894
bee44c89ac9d4e8e4e1f1c5c63088c71
f07262ac8f53755232c5abbf062364d0
2ac7c22170c00a3527eb99a2bfde2c2c
,NF,NR;cmd="echo -n " " | md5sum|cut -d\" \" -f1"; cmd|getline md5; =md5"---"cmd"---";print;}' | cat -n
but with no success to find what's going wrong.
但没有成功找到问题所在。
EDIT:As the title says, I try to replace a column in a file(a file with hundred fields). So, $1 would be $24 and NF would be 120 for a file and 233 for another file.
编辑:正如标题所说,我尝试替换文件中的一列(具有一百个字段的文件)。因此,$1 为 24 美元,一个文件的 NF 为 120,另一个文件为 233。
回答by Florin Ghita
回答by jaypal singh
I wouldn't use getline
in awk
like that. You can do:
我不会用getline
在awk
这样的。你可以做:
< tmp | while read num ; do echo -n $num | md5sum | cut -f1 -d' '; done | cat -n
回答by Ed Morton
I would GUESS, but can't tell since you aren't testing it's return code, that it's because your getline
is failing at line 7 so md5
has the same value it did for the previous line. Use of getline
is fraught with caveats and not for use by beginners, see http://awk.info/?tip/getline.
我猜,但不能说,因为你没有测试它的返回码,那是因为你getline
在第 7 行失败,所以md5
与前一行的值相同。的使用getline
充满了警告,不适合初学者使用,请参阅http://awk.info/?tip/getline。
What value are you getting out of using awk for this anyway as opposed to just staying in shell?
无论如何,与仅仅停留在 shell 中相比,您为此使用 awk 有什么价值?
回答by viraptor
It's a bit awkward with all the quoting - I'm not sure why would it fail to be honest. But here's something that uses less awk and works just fine:
所有的引用都有些尴尬 - 我不知道为什么它会不诚实。但这里有一些使用较少 awk 并且工作正常的东西:
##代码##